Writing in polar form a complex number

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Homework Statement



Write z = 1 + √3i in polar form

Homework Equations



z = r (cos\varphi + sin\varphii)

The Attempt at a Solution



Found the modulus by

|z| = √4 = 2

Now I am stuck on this part of finding the argument:

Tan-1 (√3)

now I am not sure how to go from that to the ans which is pi/3.


So would be:?

z= 2(cos(Tan-1 (√3)) + sin(Tan-1 (√3))i)
 
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when i was in complex, the unit circle became my best friend. look at the unit circle, and think about the point that z would make on the unit circle.
 
√3 / 2 would be the y coordinate of pi/3.

Just not sure how that coordinate can make the argument pi/3?
 
well, the angle pi/3 gives you √3/2, correct? And you're multiplying on the outside by 2, right?

what's cos of the same angle?

you're using a different way to make your point. So you need angles to do it in the polar form.

If you memorize 3 or 4 pairs from the unit ciricle, I think, you can figure out most common forms of numbers they give you. Unless they're being sneaky, they usually give nice proportions of pi to make pretty numbers.
 
another way of thinking about this is, what is tangent? sin over cosine. so there needs to be some argument such that sin(x)/cos(x) =√3. So look at the unit circle. what arguments involve the root of 3? π/6 does, but tan of π/6=sin(π/6)/cos(π/6)=1/√3. What else does? π/3. now what do you get?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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