Two forces P and Q are applied at the end of a screw eye in order to remove the post.
1.)variations (plots) of P and Q versus (theta) for a given value. R=800 N
2.) for what value of theta we obtain P=Q?
The Attempt at a Solution
I went ahead and found the reaction equations and combined them and got
I need to write this equation as f(theta)=0
Now using Matlab and trying a newton-raphson method I have to write a program that includes P=400 N to 800N in step sizes of 0.25 N. I need to compute theta for each P.
Plot P and Q versus theta on same coordinate. .
This is what I came up with so far for the program.
x0=400; n=16; eps=0.001; fun=@(tha) 2*p*sin(tha)*cos(30)+p*cos(tha)-800=0; fund=@(x) p*(2*cos(30)*cos(x)-sin(x); nr=(x0,n,eps,fun,fund)
function nr(x0, n, eps, f, fd)
fprintf ('%4d %8.4f %8.4f %8.4f\n',i,func, dfunc, x)
if abs(x-x0) < eps , break, end