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## Homework Statement

Two forces P and Q are applied at the end of a screw eye in order to remove the post.

1.)variations (plots) of P and Q versus (theta) for a given value. R=800 N

2.) for what value of theta we obtain P=Q?

## Homework Equations

(2*P*sin(theta))*cos(30)+P*cos(theta)-800=0

## The Attempt at a Solution

I went ahead and found the reaction equations and combined them and got

(2*P*sin(theta))*cos(30)+P*cos(theta)-800=0

I need to write this equation as f(theta)=0

Now using Matlab and trying a newton-raphson method I have to write a program that includes P=400 N to 800N in step sizes of 0.25 N. I need to compute theta for each P.

Plot P and Q versus theta on same coordinate. .

This is what I came up with so far for the program.

x0=400; n=16; eps=0.001; fun=@(tha) 2*p*sin(tha)*cos(30)+p*cos(tha)-800=0; fund=@(x) p*(2*cos(30)*cos(x)-sin(x); nr=(x0,n,eps,fun,fund)

function nr(x0, n, eps, f, fd)

func=f(x0); dfunc=fd(x0);

for i=400:n

x=x0-func/dfunc;

fprintf ('%4d %8.4f %8.4f %8.4f\n',i,func, dfunc, x)

func=f(x); dfunc=fd(x);

if abs(x-x0) < eps , break, end

x0=x;