X and y coordinates, integration, semicircular plate (masteringphysics)

AI Thread Summary
The discussion focuses on calculating the x- and y-coordinates of the center of mass for a semicircular metal plate using integration. The mass of the plate is defined as M = (1/2)ρπa²t, and the participants emphasize the importance of symmetry in simplifying the calculations, particularly noting that the x-coordinate is zero due to symmetry. To find the y-coordinate, a substitution method involving y√(R² - y²) is suggested, although there is some confusion about its reference in textbooks. Participants agree that expressing dm in terms of ρ and dV is crucial for solving the problem. Overall, the conversation highlights the integration approach needed to derive the center of mass coordinates effectively.
kottur
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Homework Statement



Use equations x_{cm}=\frac{1}{M}\int x dm and y_{cm}=\frac{1}{M}\int y dm to calculate the x- and y-coordinates of the center of mass of a semicircular metal plate with uniform density \rho and thickness t. Let the radius of the plate be R. The mass of the plate is thus M=\frac{1}{2}\rho\pia^{2}t.

Use the coordinate system indicated in the figure.

YF-08-51.jpg


1. Calculate the x-coordinate of the center of mass of a semicircular metal plate. Express your answer in terms of the variables a, ρ and t.

2. Calculate the y-coordinate of the center of mass of a semicircular metal plate. Express your answer in terms of the variables a, ρ and t.

Homework Equations



I think these:

\vec{r_{cm}}=\frac{m_{1}\vec{r_{1}}+m_{2}\vec{r_{2}}+...}{m_{1}+m_{2}}

But instead of the sum I need to integrate, right?
Does this equation work in 3D?

The Attempt at a Solution



I'm not sure how to use the equation and what information to use where.

To find x-coordinate:

x_{cm}=\frac{Mx_{cm}}{M}=x_{cm} ??

y_{cm}=\frac{My_{cm}}{M}
 
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Well I can tell you a couple of things. Because of symmetry, you don't need to use the z coordinate, you already know the z coordinate of centre of mass. I would also say the same thing for the x coordinate. So the only coordinate that you need to iron out is the y coordinate.

EDIT: You will have to put dm in terms of something else I believe.
 
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But how do I find the x coordinate in terms of rho, a and t?
 
Is x=0 by symmetry?
 
kottur said:
Is x=0 by symmetry?

yes sir, because you go from -R to R.

The best day to find y is ysqrt(r^2-y^2) and do a substitution
 
I got the answer \frac{4a}{3\pi} from a friend but I want to know how to get there!

How does that work with y=y\sqrt{r^{2}-y^{2}}?

I haven't seen that in my textbook.
 
darn i forgot that textbook kind of sucks :(. maybe forget that method since you won't be able to reference it easily
 
Thanks anyway... :) :/
 
dm can be written in terms of rho dV. this rho will cancel out which gives you the clue that you're headed in the right direction. You just have to perform dV properly.
 
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