X/y intercept for translations of f(x)

  • Thread starter Thread starter roger
  • Start date Start date
AI Thread Summary
The discussion focuses on how transformations of the function f(x) = x^2 + 2x + 2 affect its x-intercept, y-intercept, and vertex. Participants suggest converting the function into vertex form, f(x) = (x-h)^2 + k, to analyze changes more clearly. The transformation af(x) indicates a vertical stretch, impacting the y-values but not the x-intercept. The effects of other transformations like f(ax), -f(x), and f(-x) on intercepts and vertex are also explored. Understanding these transformations is essential for predicting how the graph will change based on the specific function.
roger
Messages
318
Reaction score
0
Hello

please can you guys help me on this :

f(x) = x^2 + 2x + 2

af(x)=
f(ax)=
-f(x)=
f(-x)=


In each of the cases above, I wanted to know given a function, does the graph of it change in terms of the x intercept , y intercept and vertex ?

Does it depend on the particular function or not ?


Thanks in advance.

roger
 
Physics news on Phys.org
Why don't you first change that equation into transformation/vertex form
<br /> f(x) = (x-h)^2 + k<br />

The make up numbers for a and see how it changes.
 
af(x) represent the graph of f(x) is enlarged a times of the oringinal to the y-axis.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top