Understanding XRay Emission: Maximum Frequency and Derivation Explained

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In X-ray emission, an electron is accelerated through a potential difference of 70,000 volts, resulting in the emission of an X-ray photon upon reaching the anode. The maximum frequency of the emitted X-ray can be calculated using the energy of the electron, which is derived from the equation E = eV, where E is energy, e is the charge of the electron, and V is the potential difference. This energy can then be converted to frequency using the equation E = hf, where h is Planck's constant and f is frequency. The discussion emphasizes the need for a clear understanding of these derivations to answer the initial question effectively. Understanding these principles is crucial for grasping the mechanics of X-ray production.
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Sorry if this is the wrong forum.

There is a cathode and an anode and one is emmiting an electron (whichever one of the two does that, I honestly forget)

The electron moves through a electric potentinal of 70,000 volts. When it reaches the other side an Xray photon is emitted.

1) What is the maximum frequency of the XRay wave.

and how is that derived
 
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I won't be giving you any more hints as you have not shown any effort nor have you stated what you know.

Find the energy of the electron.
 
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