Zero-momentum frame - total momentum in this frame

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Homework Statement



Assume that all particles are non-relativistic, that the target X is initially at rest,
and that x has kinetic energy Tx in the laboratory frame. Show that the total kinetic
energy of the reactants in the centre-of-mass frame is given by T* = μTx/mx, where mx is
the mass of particle x and μ the reduced mass of x and X. Also obtain an expression for
p* in terms of T* and μ.


Homework Equations



I have completed the first part of this question without a problem. The second part, requiring p* to be found doesn't make sense to me. Surely the total momentum in the zero-momentum frame should be zero? Or is it expecting a different quantity?


The Attempt at a Solution



First part done. Second part - don't know what it is asking.
 
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I agree. The problem isn't clear. One possible interpretation is that p* is the momentum of the incoming particle - as opposed to total momentum - as seen in the center of mass ref. frame.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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