Recent content by angela107

Thank you!

I see. There are two subsets; ##∅##, and the subset itself.

For ##{∅}##, I've come to the conclusion that there is only one subset because it has the empty set and itself as subsets. In this case, there are the same thing. For ##{0}##, there should be two subsets; the empty set and the set itself. Am I right?

##A ∖ B## can't include any elements that are not in ##A##, so it is the same as saying ##A∖(A∩B)##; it's exactly the elements of ##A## except those in ##A∩B##. ##A∖(A∖(A∩B))## is exactly the elements of ##A## except those in (exactly the elements of ##A## except those in ##A∩B##). This is the...

Sorry, I didn't notice I had two different R's! I will make a correction. Thank you :)

A concentric cirlce has two circles with the same center, but a different radii. We are given a pie with radius ##r##. A circular cut is made at radius ##r## such that the area of the inner circle is ##1/2## the area of the pie. We know that the formula to calculating the area of a circle is...

The domain and range of this function will be the same. We can let ##𝑓(𝑥)=\sqrt{x},𝑥≥0## However, ##𝑦=𝑓(𝑥)≥0##, so the domain and range of ##f## are ##[0,+∞)## And since ##f## is a function, ##f^{-1}s## domain is the range of ##f## and ##f^{-1}s## range is ##f’s## domain. In other words...

As the question asks, I believe this statement is true. At least, technically. It is important to consider the domain of the function. Yes, ##sqrt(x)^2 = x##, but ##sqrt(x)## is only defined for nonnegative ##x##, whereas ##sqrt(x^2)## is defined for all ##x##, since ##x^2## is always...

If I remove the Cl- ions, I would have to replace them with something else, as long as there is no precipitate involved.

I wasn't told to perform an action that could disrupt the equilibrium, I just need to find a way to add ions by any means necessary as long as I don't produce any precipitate. Removing Cl- ions could do the job...

Here's an image of the equilibrium I'm not sure how that's possible, but I'm thinking maybe I could remove Cl- ion so that the Ag+ ions don't have much to combine with.

Summary:: In the question below, I've been asked to determine what happens to the reaction when the temperature is increased. I know the answer is a, but I'm having difficulty determining why. https://www.physicsforums.com/attachments/264126

If an endothermic reaction has a lower temperature, since the forward reaction rate decreases more, the reaction should produce more energy to compensate for the decreased energy and raise the rate of the forward reaction until it reaches equilibrium with the reverse reaction. Is this saying...