Recent content by Gourab_chill
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Chemistry How should I proceed with the reactions?
The question: How will the first reaction take place for instance? Is CH3S- the nucleophile? Will it be added to the oxygen and the other hydrogen(H+) get attached to the other oxygen, with the double bond shifting to the center(C2-C3)? If this is right then where will CN- will attack?- Gourab_chill
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- Organic chemistry Reactions
- Replies: 1
- Forum: Biology and Chemistry Homework Help
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What is a "Torsional Constant"?
I have a bit confusion as I overlooked a few things(my bad): I thought the given angular velocity(ω0) shouldn't change but here as in the solutions I see they're considering ω0 to change with ω = √(C/I) [as ω0= ωβsin(ωt)]! Please explain me a bit here.- Gourab_chill
- Post #11
- Forum: Introductory Physics Homework Help
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What is a "Torsional Constant"?
Yes, I agree to this analogy too.- Gourab_chill
- Post #10
- Forum: Introductory Physics Homework Help
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What is a "Torsional Constant"?
Since this pendulum is spinning it is coming to rest and then going the opposite way(harmonic motion i mean) so there is some some force in the wire which causes it to accelerate in the opposite direction, and therefore there must be some angular acceleration, right?- Gourab_chill
- Post #8
- Forum: Introductory Physics Homework Help
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What is a "Torsional Constant"?
Thanks again! So Cθ = Iα is the equation, and therefore ω^2=C/I.- Gourab_chill
- Post #6
- Forum: Introductory Physics Homework Help
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What is a "Torsional Constant"?
Thanks, now I understand it! What are your views on the first equation [ ω=√(C/I) ]? That equation seems familiar to the other ones like ω=√(mgd/I), I'm confused on what exactly C means.- Gourab_chill
- Post #3
- Forum: Introductory Physics Homework Help
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What is a "Torsional Constant"?
The question was: I will also include the solution: So, what is the justification of the first formula [ω=√(C/I)]? I know how to derive simple harmonic equations, this one as I guess is probably similar? But I cannot connect as to how C is used exactly. And the second formula [ω'=ωβ], I...- Gourab_chill
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- Angular velocity Constant Moment of inertia Rotational motion
- Replies: 11
- Forum: Introductory Physics Homework Help
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Confusion on the distribution of charge
So, can I conclude from this is that the charge will distribute in such a way that there will opposite charge along the patch facing the charge q such that the electric field by it(charge q) will not be expressed inside the conductor/block and the charge on the the other patch of the block will...- Gourab_chill
- Post #7
- Forum: Introductory Physics Homework Help
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Confusion on the distribution of charge
I couldn't get what you meant by 'multiplication by constant', is it the net charge (q1+q2) you mean?- Gourab_chill
- Post #5
- Forum: Introductory Physics Homework Help
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Confusion on the distribution of charge
No. Until there is some charge in the cavity, I think. Another clarification I wanted to make on the second para, first line(of the main question body): Actually this line has typos in it and I regret for not checking will I was typing it. I wanted to type: "I know the charges induced on the...- Gourab_chill
- Post #3
- Forum: Introductory Physics Homework Help
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Confusion on the distribution of charge
The charges are q1,q2 & q. P,Q,O1,O2 refer to positions only. This is a conducting sphere with cavities containing charges. I'm interested in knowing how the charge should be distributed in the sphere. I know the charges induced on the charges of the sphere should be equal and opposite to the...- Gourab_chill
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- Cavity Charge Conductors Confusion Distribution Electric field
- Replies: 7
- Forum: Introductory Physics Homework Help
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Why is the power of a particle on a wave zero in a stationary wave?
Yes, I agree with this- Gourab_chill
- Post #19
- Forum: Introductory Physics Homework Help
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Why is the power of a particle on a wave zero in a stationary wave?
Yes, at a point the power is zero but over a region the power is zero as energy flux is zero, right?- Gourab_chill
- Post #17
- Forum: Introductory Physics Homework Help
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Why is the power of a particle on a wave zero in a stationary wave?
But this is not a standing wave, but shouldn't the power be zero across two points? You said power should be zero assuming it as a standing wave- Gourab_chill
- Post #15
- Forum: Introductory Physics Homework Help
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Why is the power of a particle on a wave zero in a stationary wave?
This is not a standing wave, but I'm confused as you said "if the wave is stationary";there are two types of waves- moving waves and stationary waves, right?- Gourab_chill
- Post #13
- Forum: Introductory Physics Homework Help