Recent content by icelevistus

you're right, as I was writing it I thought I was using cosine and it would introduce a sign error. Whole shell it is!

Express the current density of a spherical shell of radius a, rotating with angular velocity omega, with surface charge density sigma Delta function will be denoted d(x). Spherical coordinates will be used I have concluded that for a given chunk (if we restrict to the 0<theta<pi/2...

Sorry, looks like that Mathematica code was no good. Is it still legible?

A particle is described by the wave function \[CapitalPsi] (\[Rho], \[Phi]) = AE^(-\[Rho]^2/2 \[CapitalDelta]^2) (Cos[\[Phi]])^2 Show P (Subscript[l, z] = 0) = 2/3 P (Subscript[l, z] = 2 h) = 1/6 P (Subscript[l, z] = -2 h) = 1/6 I have already used...

I solved the problem, it turned out that including the potential of the point particle in the expansion did not cause as many problems as I had initially anticipated. Thank you for the help.

(I deduced that the potential far from the sources should reduce to just the potential of the point charge, since the dipole part of the sphere will die out)

OK, so for the outside potential, all the positive powers of r have zero coefficients. I went through the other BCs for this, but you're left with two equations relating the two coefficients that can only be solved by setting all the coefficients equal to zero.

Consider a sphere of radius a with dielectric constant epsilon. A point charge q lies a distance d from the center of the sphere. Assume d > a, calculate the potential for all points inside the sphere, and outside the sphere. The problem is to be solved with an expansion of Legendre...

To get mystical, the friction results in the system not being isolated. You end up having to consider the whole world(!)

Discrete photons are not separated into transmitted and reflected portions when they travel through a partially reflecting surface. They simply have a one-time probability of passing through or not passing through. This probability gives the relative proportions of transmission and reflection...

his question was about rotating the Earth about an equatorial axis, not polar axis. For this, you have to consider that you are going against the force of the Earth's angular momentum vector. I haven't the desire to calculate it, but suffice to say that it is far more than all the king's...

As I feared, introducing the particulars of the thought experiment would result in too much focus on the apparatus. Very well: Use just one mirror, shoot the first photon at it from far, far away. Then on the opposite side, shoot the other photon such that it will coincide with the...

To experimentally quantify how this may be done: consider the first photon is bouncing in a loop bounded by partially reflecting surfaces (lets just say its bouncing back and forth between two partially reflecting mirrors). The second photon is the fired (by whatever means, say the energy...

Are you suggesting that the energy left the photons and permeated out into space some way in some other form?

I agree that the use of "irrational" is having a destructive effect on what you're trying to say. "Irrational" implies that there is not rigorous reasoning behind something, which there is for all accepted physics. Perhaps the word you are looking for is "counter-intuitive"? Unfortunately...