Recent content by Jordash

I discovered that that is the conjugate and I came out with this: 27-6sqrt(t)-tsqrt(t) ---------------- 9-t So in other words, that limit does not exist. Is that right?

Problem Calculating a limit with a square root, I'm stuck :( Homework Statement The limit is equation 9-t / 3-sqrt(t) as t approaches 9 I'm stuck on the how to simplify this? Thanks for any help. Homework Equations The Attempt at a Solution

I'm sorry but both of those answers made no sense...

Homework Statement The figure shows the graph of a cubic polynomial. The function graphed is f(x)= Hint: You may write the function as f(x) = a(x-b)(x-c)(x-d) where b, c, and d, are integers and a is a fraction. Homework Equations The Attempt at a Solution I'm lost...

Homework Statement How would you solve this problem: x^2 - 5x >= 0 Homework Equations The Attempt at a Solution I think it might be something to do with the Quadratic Formula?

Actually would I be correct in saying that all like terms would be combined? because D'+D'+D'=D' so the simplified form of the equation above would be AB'+D' Is that right or am I completely crazy?

Homework Statement I came to an equation which looks like this: AB'D' + AC'D' + CD' I know I can simplify out the C to this AB'D' + AD' + D' Any further simplification available (And am I simplifying properly so far?) Thanks Homework Equations The Attempt at a Solution

Let me throw another one out there to hopefully make it easier to understand (don't worry about the transfer function) so 2.2e3/2.2e3+i2pi10e-3 How would that be simplified or in simpler terms a/a+b How would you simplify that The problem above would be i*2pi*f*L/R+i*2pi*f*L f is the...

My algebra is really rusty, anyway I'm trying to simplify a Transfer Function so I have H(jw)=ZL/R+ZL so ZL is the impedance of an inductor and R is the impedance of the Resistor, my question is how would I go about simplifying that transfer function into it's simplest form? Thanks...

Oh yeah your right, thanks for catching that.

Oh and Quick question about Calculating Vb I know that I can use the Voltage Divider Rule to get it (I did that for Va) For Vb would I use the total impedance of all the impedances above the 820 ohms as say Z1 and then the impedance of the 820 Ohm resistor so it would be Vb=V*...

I'm glad it's right, The book tries to simplify things by adding the ohms to help us realize that impedance is similar to ohms when the book get's more complicated it shows the actual capacitance. So I guess the book is kind of in "Training Wheels" mode at the moment :)

I have a circuit here: And I simplified it like so: Did I do it correctly? Thanks, Jordan

i is what you would actually put into a calculator i=sqrt(-1) or something like that.

i is what you would actually put into a calculator i=sqrt(-1) or something like that.