Recent content by russdot
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Does \(A e^{iA} = e^{iA} A\)?
Ah yes, so since e^{A} is defined with a power series e^{A} = 1 + A + \frac{A^{2}}{2!} + \frac{A^{3}}{3!} + ... and A commutes with itself then A would commute with e^{A} Thanks!- russdot
- Post #3
- Forum: Advanced Physics Homework Help
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Does \(A e^{iA} = e^{iA} A\)?
If A is an operator, is it correct/allowed to say: Ae^{iA} = e^{iA}A Thanks- russdot
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- Operators
- Replies: 2
- Forum: Advanced Physics Homework Help
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Equating integrands on two equal integrals?
Homework Statement This is more of a general question. If I have two different integrals that equal the same value, is it valid to equate the integrands? Homework Equations \int P(\theta,\phi)d\Omega = N \int Q(\theta',\phi')d\Omega' = N Where N is a constant and d\Omega = sin\theta...- russdot
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- Integrals
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Graduate View from a spaceship at relativistic speeds
JesseM, Thanks for the reply, those links helped a lot :)- russdot
- Post #3
- Forum: Special and General Relativity
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Graduate View from a spaceship at relativistic speeds
If one was in a spaceship at rest in frame K and sees an evenly-distributed number of stars around them, what would the distribution of stars look like if you were traveling at relativistic speeds (frame K')? I'm conflicted because I've seen animations online that seem to illustrate the stars...- russdot
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- Relativistic Spaceship
- Replies: 3
- Forum: Special and General Relativity
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How Do You Simplify Complex Fractions with Nested Radicals?
Homework Statement \frac{1 + \sqrt{\frac{1}{1 + \left(\frac{s}{u}\right)^{2}}}}{1 - \sqrt{\frac{1}{1 + \left(\frac{s}{u}\right)^{2}}}} Should equal \left(\sqrt{1 + \left(\frac{u}{s}\right)^2} + \left(\frac{u}{s}\right)\right)^{2} Homework Equations above The Attempt at a Solution...- russdot
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- Complex Fractions
- Replies: 1
- Forum: Precalculus Mathematics Homework Help
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Magnetic field above a thin charged disc
For the magnetic field of each loop (along Z axis), I get: \vec{B}(z) = \frac{\mu_{0}}{4 \pi} \int \frac{\sigma 2 \pi \omega x'^{2} (\hat{\phi} \times \hat{r})dx'd\phi}{x'^{2} + z^{2}} where \hat{\phi} \times \hat{\r} = \hat{k}cos\psi + \hat{R}sin\psi (\psi is the angle between\vec{r} =...- russdot
- Post #8
- Forum: Advanced Physics Homework Help
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Magnetic field above a thin charged disc
Ah yes, I really should eat some food... but since \vec{I} = \lambda \vec{v} and \lambda = \sigma 2 \pi dr and \vec{v} = r \vec{\omega} then \vec{I} = \sigma 2 \pi \vec{\omega} r dr, correct?- russdot
- Post #6
- Forum: Advanced Physics Homework Help
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Magnetic field above a thin charged disc
Hi gabbagabbahey, Thanks for the tips, I'm still getting used to the LaTeX notation. marcusl, Ok, and then each infinitesimal loop will have a current I = \sigma 2 \pi R dr.- russdot
- Post #4
- Forum: Advanced Physics Homework Help
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Magnetic field above a thin charged disc
Homework Statement A thin disc of radius R carries a surface charge \sigma. It rotates with angular frequency \omega about the z axis, which is perpendicular to the disc and through its center. What is B along the z axis? Homework Equations General Biot-Savart law: B(x) =...- russdot
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- Charged Disc Field Magnetic Magnetic field
- Replies: 8
- Forum: Advanced Physics Homework Help
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Potential inside (and outside) a charged spherical shell
Yes, you're right. The form I used was ambiguous, sorry about that! I guess I just jumped right to using R^{2}sin\theta' d\theta' d\phi as the surface area element. I have solved the problem though, thanks for the assistance!- russdot
- Post #5
- Forum: Advanced Physics Homework Help
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Potential inside (and outside) a charged spherical shell
Well d^{3}x' turns into r^{2}sin\theta dr d\theta d\phi and since r is constant at R (spherical shell) then an R^2 comes out of the integral and cancels the R^2 in the denominator from the charge density rho = Q / (4 pi R^2). I also figured out the problem, after integration: V(x) =...- russdot
- Post #3
- Forum: Advanced Physics Homework Help
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Potential inside (and outside) a charged spherical shell
[solved] Potential inside (and outside) a charged spherical shell Homework Statement Use the integral (i) to determine the potential V(x) both inside and outside a uniformly charge spherical surface, with total charge Q and radius R. Homework Equations (i) V(\vec{x}) =...- russdot
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- Charged Outside Potential Shell Spherical Spherical shell
- Replies: 5
- Forum: Advanced Physics Homework Help
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Mean radius, r.m.s. radius of nucleus
Great, thanks! I'm assuming if the rms equation is correct, then the mean value equation is also correct..- russdot
- Post #3
- Forum: Advanced Physics Homework Help
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Mean radius, r.m.s. radius of nucleus
Hello, Given a particular charge distribution p(r) = p_0*exp(-r^{2}/a^{2}), I was wondering if the proper way to calculate the mean radius <r> would be \intp(r)*r*p(r) dV ? Which would make <r^{2}>^{1/2} = (\intp(r)*r^{2}*p(r) dV)^{1/2}, correct?- russdot
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- Mean Nucleus Radius
- Replies: 3
- Forum: Advanced Physics Homework Help