Recent content by simo

Nope, that's how I made it. If I disconnect the output/diode junction from ground, would it sink the current?

Can you tell me what is wrong with my timer. I want it to make a relay open and shut periodically. For some reason it's not working.

Well I didn't want to say because I didn't want to be scrutinized, but this would be a good opportunity for you all to explain how this device fails, if it fails. And you're not allowed to say the first law of thermodynamics because that's too obvious. What I'm trying to design is a...

Thanks again Redbelly98, I guess I won't be building this device.

Cool, thanks.

If the method of images is applied to a conducting sphere and a point charge, it can be shown that the two will attract. Therefore, I will try charging a single plate and getting rid of the other.

Are you asking about the acceleration due to gravity? If so, yes. The gravitational foce will cause you to accelerate, hence your velocity (along with your kinetic energy) would increase. K=.5mv^2 A weaker G-field will just make you accelerate slower.

The field should cause a charge separation inside the BB because its a conductor, right?

I want to create an electric field that will cause a copper BB to move. So far I have tried using a 9V battery with the positive end attached to a metal sheet and the negative attached to another sheet, like a capacitor. Unfortunately this hasn't worked. Any ideas?

Yea, I didn't have it in the right form. It's for a physics class, so the books says to use a table to help. I think I will try to solve it out anyway. Thanks for the help.

Homework Statement solve the integral: ∫_(-∞)^∞▒〖x^2 e^(-λ(x-a)^2 ) 〗 dx where λ and a are positive real constants The Attempt at a Solution I tried integration by parts with and without y-substitution but neither worked for me. Without substitution, I set up the integral to look...

No, I've never heard of this. I'm new to electronics and was hoping to use the 555 timer because I understood it.

I'm planning on using a 556 timer for a 3-way solenoid valve. I need to have both valves closed for a period of 10 seconds, then open the first valve for 20 ms, followed by the opening of the second valve for 20 ms. This is astable. Is it possible to line up the timing using a 556 timer or do...

Right, initially I thought there was no field because I calculated it to equal zero. Then I realized that the potential is relative and can have whatever value. This material is best understood if you graph the potentials for the two cases.

Ok, I think I figured it out. See if you can follow my logic. First of all, the potential is whatever you define it to be because you can add a constant. For the proton in the middle of two other protons, its potential is the same as a proton the same distance away from a particle of...