Given $$P(B \land C)$$ will it always be true that $$P(B \land C | A) P(A) + P(B \land C | \lnot A) P( \lnot A)$$ (regardless what $P(A)$ would be)?
How can I prove this?
Given this base data (taken from Graphical Models )$P(C) = 0.5$
$P(\lnot C) = 0.5$
$P(R | C) = 0.8$
$P(R | \lnot C) = 0.2$
$P(\lnot R | C) = 0.2$
$P(\lnot R | \lnot C) = 0.8$
$P(S | C) = 0.1$
$P(S | \lnot C) = 0.5$
$P( \lnot S | \lnot C) = 0.5$
$P( \lnot S | C) = 0.9$
$P(W | \lnot S, \lnot...
No -- there are 25 reservations every day. And there is a 0.8 probability that a reservation is claimed.
Therefore, each day it is expected that 20 cars will be claimed (25 * 0.8).
The probability that 23 or more of reservations are claimed ${{25}\choose{23}} {0.8 ^{23} * 0.2^ 2}$ +...
So, at a car rental company, 20% of car reservations are not claimed. There is a total of 22 cars and the manager takes 25 reservations a day.
If all cars are claimed for a day, what is the probability that one or more customer who had reservations were unable to claim their car?
I need to...
I'm getting these concepts confused.
If I have an object called $x$, and I have five places or slots to put the object, how many ways could 2 $x$s be places in the 5 spaces?
Example:
x x _ _ _
x _ x _ _
x _ _ x _
x _ _ _ x
_ x x _ _
_ x _ x _
_ x _ _ x
_ _ x x _
_ _ x _ x
_ _ _ x x
So in...
I have $P(B) = 0.4$ and $P(\lnot B) = 0.6$.
$P(TS|B) = 0.7$ and $P(TS|\lnot B) = 0.25$
$P(B|TS) = 0.65116$ and $P(\lnot B|TS) = 0.34884$ (from bayes theorem).
Now, if we get $B$ or $\lnot B$, and we get the same event twice in a row so we get $B$ then $B$ or $\lnot B$ then $\lnot B$, what...
How to translate "there exists exactly one happy person" into predicate logic?
I came up with $$ \exists x : happy(x) \implies \forall y: happy(y) \land y = x$$. But this is incorrect.
I also tried $$\exists x: happy(x) \land \forall y: happy(y) \land x = y$$. This is also incorrect.
The...
A coin is tossed 4 times.
Is there a way to determine mathematically what is the probability that exactly 2 heads occur?
By drawing a decision tree I can determine that it is 6/16, but this seems like an arduous process for larger numbers.
Is $$x^\frac{2}{3} (\frac{5}{2} - x)$$ a continuous function for all values of x?
It seems disjointed at $x = 0$ but the limit as x approaches 0 is 0 from both sides of x.
If anyone value in an expression is approaching 0, does the entire expression equal 0?
So for example, for the limit $\lim_{{z}\to{q}} z ln(z) f(z)$. If $\lim_{{z}\to{q}}f(z) = 0$, then does $\lim_{{z}\to{q}} z ln(z) f(z)$ equal 0?
I have:
$$\int_{1}^{3} \frac{1}{\sqrt{3 - x}} \,dx$$
I can do $u = \sqrt{3 -x}$, and $du = \frac{1}{2 \sqrt{3 - x}} dx $ and $dx = 2 \sqrt{3 - x} du $. Plug into original equation:
$$\int_{1}^{3} \frac{2 u }{u} \,du$$ and $2 \int_{1}^{3} \,du = 2u = 2 \sqrt{3 - x} + C$
So $(2\sqrt{3 - 3})...
I have:
$$\int_{1}^{2} \frac{1}{x lnx} \,dx$$
I can set $u = lnx$, therefore $du = \frac{1}{x} dx$ and $xdu = dx$. Plug that into the original equation:
$$\int_{1}^{2} \frac{x}{x u} \,du$$
Or
$$\int_{1}^{2} \frac{1}{ u} \,du$$
Therefore: $ln |u | + C$ and $ln |lnx | + C$
So I need to...