Calculating Wave Speed of a Sinusoidal Wave with a Given Equation

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The sinusoidal wave is represented by the equation y=(0.30 m)sin(0.20x-40t), where 0.30 m is the amplitude. The term 0.20x corresponds to the wave number (k), while -40t represents the angular frequency (w). The wave speed can be calculated using the relationship v = w/k, where w is the angular frequency and k is the wave number. The discussion highlights the need for clarity in understanding the components of the wave equation. The problem-solving approach indicates a transition to a more appropriate forum for homework assistance.
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pls help me on this problem, thanks a lot.


A sinusoidal wave is described by y=(0.30 m)sin(0.20x-40t). Determine the wave speed.
 
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What are the individual parts of the sin wave? 0.30 would be your amplitude, right? Break it down. What is the .20x and -40t?

A sin wave holds the form y = Asin(wt - kx + phase shift) + D, where D is DC offset. w is in rad/sec. K is .20, which is your WAVE number. K = 2*pi*f/c = 2*pi/lambda = w / c. Go from there.

This should probably be moved to the HW forums.
 
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Thanks

I got it.
 

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