Formula for mixing liquids of different temperatures?

AI Thread Summary
To achieve a target temperature of 40 degrees Celsius when mixing 3500 liters of water from a hose at 10 degrees Celsius and boiled water at 100 degrees Celsius, a calculation suggests using approximately 1166 liters of boiling water. The method used assumes a simple weighted average for temperature mixing, which is generally adequate for practical purposes. While thermal expansion could be considered for precision, it may not be necessary for typical applications like filling a pool. A suggestion was made to conduct a small-scale test using 3.5 liters to verify the calculations before proceeding with the larger volume. Overall, the discussion emphasizes the feasibility of using the weighted average method for mixing liquids of different temperatures.
kenewbie
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I'm going to fill a big container (3500 litres) with water. I'll use water from a hose, and boiled water, and I want to hit 40 degrees celcius.

Now, I figured that this was straight forward,

Temperature in hose = 10 C
Temperature of boiled water = 100 C

( 100 * X + (3500 - X) * 10 ) / 3500 = 40

Which gives 1166 litres of boiling water.

However, this assumes that 1 litre of 10 C water + 1 litre of 20 C water = 2 litres of 15 C water. In other words, that I can just add the temperatures together and then divide by the total amount of liquid.

Someone (who unfortunatly was not able to provide a formula) said it is not as straight forward as that.. so, I'm looking for the formula for mixing liquids of different temperatures.

k
 
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How precise do you need to be? I guess you could take thermal expansion into account if you wanted to, but the simple weighted-average method you used should be good enough for most applications.
 
Oh, ok then I am golden. I only need to be accurate enough to avoid boiling anyone that ventures into the pool :)

Thanks a lot.

k
 
You could also do a test by making 3.5 liters first, using 1.17 L of boiling water.
 
Yeah, I'll do a small scale test first, to make sure.

Thanks again.

k
 
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