Why do lone pair electrons repel each other more strongly ?

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In VSEPR theory, lone pairs of electrons exert stronger repulsion than bonding pairs, influencing molecular geometry. This stronger repulsion occurs because bonding pairs are involved in sigma bonds with other atoms, placing them further from the central atom's nucleus compared to lone pairs. Additionally, the repulsion between electrons on the same atom is greater than that between electrons on different atoms. In covalent bonds, typically only one electron from each bond is associated with a given atom, while lone pairs consist of two electrons, further contributing to their stronger repulsive effect. Understanding these principles is essential for grasping molecular shapes and structures in chemistry.
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In VSEPR theory, lone pairs repel each other more strongly than bonding pairs do, therefore they bend the molecule and determine its geometry.

But why does that happen? What makes the repulsion stronger?

Thanks for your help
 
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annatar said:
In VSEPR theory, lone pairs repel each other more strongly than bonding pairs do, therefore they bend the molecule and determine its geometry.

But why does that happen? What makes the repulsion stronger?

Thanks for your help

Because a bonding electron pair is involved in a sigma bond with another atom. Hence is at a greater distance from the nucleus of the central atom than a non bonding pair. I think you can find explained in those lectures all basic concepts of chemistry

http://ocw.mit.edu/OcwWeb/Chemistry/5-112Fall-2005/VideoLectures/index.htm
 
There are two points of importance, here:
1. The repulsion between electrons on different atoms is much smaller than between electrons on the same atom.
2. In a truly covalent bond, there is only one electron of the two per bond (at least on the mean) at a given atom as compared to two in a lone pair.

This is most clear in the limit, where the atoms are very far apart.
 
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