Single circular loop of wire filled with a uniform magnetic

AI Thread Summary
The discussion focuses on a physics problem involving a circular loop of wire in a changing magnetic field. The magnetic field is defined by the equation B(t) = B0 exp{-t / 2.15 sec}, and the task is to find the value of B0 when the induced emf is 1.00 V at t = 0.25 sec. The user attempts to apply the formulas for magnetic flux (Φ = BA) and induced electric field (E = -dΦB/dt) to solve the problem. They express uncertainty about their approach and seek confirmation on whether they are using the correct formulas for part (a) of the question. Clarification on the application of these equations is needed to ensure accurate calculations.
yekidota
Messages
3
Reaction score
0

Homework Statement


The figure to the right shows a single circular loop of wire
filled with a uniform magnetic field pointing into the page
The radius of the loop is R = 1.75 cm. The magnitude
of the magnetic field in the loop is changing
according to B(t) = B0 exp{-t / 2.15sec}
(a) what is the value of B0 if at t = 0.25 sec
the magnitude of the induced emf in
the loop is 1.00 V?
(b) what is the magnitude of the induced electric field inside
the loop at a distance

Homework Equations


Φ=BA
E=dΦB/dt

The Attempt at a Solution



Φ=BA = (B0^-t/2.15)π1.75^2

E=dΦB/dt =-AdB/dt=-(π1.75^2)((d(B0^(-0.25/2.15)))/dt
 
Physics news on Phys.org
am i using the right formula?
I wanted to know if I am on the right track for a)
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top