BOTE calculation. See here:
http://www.asianewsnet.net/home/news.php?sec=1&id=17975"
"The radiation level at the scene before the operation was 4.13 millisieverts per hour at an altitude of about 300 meters and 87.7 millisieverts per hour about 100 metres above ground."
The inverse square law would imply a 9 fold increase in radiation from 300 metres to 100 metres. Instead we see a 87.7/4.13 = 21.2 fold increase. (I am still looking for data on gamma ray attenuation in air.)
Now the inverse square law strictly only applies to a point source. We can only extrapolate to the effective cross sectional area of the source from the angle of the helicopter. Let's extrapolate to 2 metres from the source (4 square metre cross section).
If we assume 4.13 millisieverts per hour at 300 metres and no attenuation, we would estimate 4.13*(300/2)^2 = 93000 millisieverts per hour = 93 sieverts per hour = 9300 REM/hr.
If we assume 87.7 millisieverts per hour at 100 metres and no attenuation, we would estimate 87.7 *(100/2)^2 ~ 220,000 millisieverts per hour = 220 sieverts per hour = 22,000 REM/hr ~ 22,000 Roentgens/hr.
These are Chernobyl-like estimates, but they are BOTE calculations and they ignore atmospheric attenuation.
Please check my calculations. I realize these are non-trivial conclusions. I'm hoping to find an error.