How much base to neutralize acid?

AI Thread Summary
To neutralize 100 mg of H2SO4 in 1 liter of water, the correct stoichiometric calculation shows that 81.6 mg of NaOH is required. The balanced chemical reaction for this neutralization is H2SO4 + 2NaOH → Na2SO4 + 2H2O. Each mole of H2SO4 reacts with two moles of NaOH, which is crucial for the stoichiometry. The user struggled with the reaction products and molarity calculations, indicating a need for a clearer understanding of balancing chemical equations. Properly balancing the equation is essential to determine the correct amount of NaOH needed for neutralization.
ride5150
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I have a question in my environmental engineering class that goes like this:

if 100mg H2SO4 is added to 1 Liter of water, how many milligrams of NaOH (strong base) must be added to neutralize the acid?

the answer is 81.6mg, but how do i get to the answer?

i tried writing a reaction of: H2SO4 + NaOH = 2H+ + SO2-4 + Na+ + OH-

then doing: molarity of H2SO4 times Molarity of NaOH = 10-7

but i just can't seem to find how to get the answer.

any help would be greatly appreciated
 
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This is a simple stoichiometry. Start by balancing the reaction equation - so far it even doesn't contain correct products, you just dissociated both substances. Do you know how to read balanced reaction equation?
 
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