Connected Wheels Problem. Angular Velocity.

AI Thread Summary
Wheel A, with a radius of 8.9 cm, accelerates from rest at 8.6 rad/s², while Wheel C has a radius of 30.7 cm and needs to reach a speed of 93.0 rev/min. The relationship between the angular velocities of the wheels must be considered, as they are connected by a belt, meaning they do not have the same angular speed despite having the same linear velocity. The initial calculations were incorrect due to not accounting for the differing radii and the relationship between angular and tangential velocity. To solve the problem accurately, one must apply the correct conversions and consider the impact of radius on angular velocity. Understanding these concepts is crucial for determining the correct time for Wheel C to reach the desired rotational speed.
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Homework Statement


Wheel A of radius ra = 8.9 cm is coupled by belt B to wheel C of radius rc = 30.7 cm. Wheel A increases its angular speed from rest at time t = 0 s at a uniform rate of 8.6 rad/s2. At what time will wheel C reach a rotational speed of 93.0 rev/min, assuming the belt does not slip?


Homework Equations


2 π rad = 1 Rev
v = vo + at ( constant acc)

The Attempt at a Solution


Wheel A and Wheel C have the same velocity, so I converted the rads to revs and 93 rev/min to 1.55 revs/s and divided the velocity by the acceleration to find the time. But the answer doesn't work. Am I doing something wrong ? Please help !

Thanks
 
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We need to see more of your work to know just were you went wrong. Also, note that the time to for wheel A to complete one revolution is much less than that of wheel B, yet both go through 2\pi radians and your work thus far does not take this difference into account.
 
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Define "speed". Each point on the belt will be be moving at the same rate, but translational velocity and angular velocity are not the same. Your conversion from radians to revs needs to include the fact that angular velocity depends on radius. Try looking up the conversion of tangential velocity to angular on wikipedia.
 
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