Velocity - time home work check

AI Thread Summary
The car accelerates from 0 to 30 m/s in 5 seconds, resulting in an acceleration of 6 m/s² and a distance of 75 meters. It then travels at a constant speed of 30 m/s for 15 seconds, with no acceleration, covering 450 meters. Finally, the car decelerates to a stop over 10 seconds, yielding an acceleration of -3 m/s² and a distance of 150 meters. The total distance traveled during the entire motion is 675 meters. The conversion of 30 m/s to km/h is 108 km/h.
jacknjersey
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Homework Statement



A car accelerates from 0 to 30m s ^-1 in 5.0 seconds, travels at a constant 30m s^-1 for 15.0 seconds and then brakes to a stop in 10.0 seconds.

1) calcualte the acceleration (assumed constant) in each section of the motion.
2) calculate distance travelled
3) what is 30m s^-1 in km/h?

Homework Equations



a= change in velocity / change in time
d(t) = v_0 x t + (a/2)t^2


The Attempt at a Solution



a=(30-0)/5 = 6 m/s
d(t) = 0 x 5 +(6/2_ x 5^2 = 75m

a=(30-30)/15 = 0 m/s^2
d(t) = 30 x 15 + (0/2) x 15^2 = 450m

a=(0-30)/10 = -3m/s^2
d(t) = 30 x 10 + (-3/2) x 10^2 = 150m
 
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Thanks so much! I'm working so slowly trying to get it right. Thanks again, the feedback is a boost!
 
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