Calculating the percentage of silica

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To calculate the percentage of silica in the partially dried clay mineral, start with the original sample composition: 100 g consisting of 12 g water, 45 g silica, and 43 g other components. After partial drying, the water content decreases to 8%, meaning the remaining water is 8 g. The total mass of the partially dried sample is now 100 g - (12 g - 8 g) = 96 g, with silica and other components unchanged. The percentage of silica in the partially dried sample is then calculated as (45 g silica / 96 g total) * 100, resulting in approximately 46.88%. Thus, the percentage of silica in the partially dried sample is nearly 46.88%.
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Homework Statement


A partially dried clay mineral contains 8% of water, the original sample contained 12% water and 45% silica. Then, the percentage of silica in the partially dried sample is nearly?


Homework Equations


Don't know if this is would help in the calculation,
in the original sample, 12% water is present, hence non water components are consisting of 88%


The Attempt at a Solution


Attempted one but was out of range of the concept to be used.
 
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hi xiphoid! :smile:

hint: suppose the original sample was 100 g (12 g water, 45 g silica, 43 g other stuff) :wink:
 
I had that stuff in my mind but couldn't manage to calculate further
tiny-tim said:
hi xiphoid! :smile:

hint: suppose the original sample was 100 g (12 g water, 45 g silica, 43 g other stuff) :wink:
 
xiphoid said:
I had that stuff in my mind but couldn't manage to calculate further

ok, after the sample has dried, the water is less but everything else is the same

so call it x g water, 45 g silica, 43 g other stuff, …

from the question, what equation can you find for x ? :wink:
 
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