Calculating Surface Charge Density

AI Thread Summary
To calculate the surface charge density on a copper penny given an electric field strength of 2310 N/C, the formula Surface Charge Density = Q/A is relevant. The discussion highlights the initial confusion about applying this formula to the problem. It is clarified that one can assume a constant surface charge density for the penny's surface. Additionally, the electric field of an infinite plane with constant surface charge density can be used to derive the necessary values. The problem can be solved effectively by applying these concepts.
angryshoe
Messages
1
Reaction score
0

Homework Statement


The electric field strength just above one face of a copper penny is 2310 N/C.

What is the surface charge density on this face of the penny?

Homework Equations



Surface Charge Density = Q/A

The Attempt at a Solution



The only thing that I can understand is that surface charge density is equal to Q/A but that does not seem to help me with this question. What can I do for this problem?

Edit: I figured out how to do this problem.
 
Last edited:
Physics news on Phys.org
I think [/color]you are meant to assume that the surface charge density is constant. you do know how to calculate the field of an infinite plane of constant surface charge density, right?
 
Last edited:
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Back
Top