Griffiths Electrodynamics book: Electric potential

In summary, The two infinite parallel plates are at potential 0 and V_0. The potential in between the plates is V_0(x/s). The charge densities in between the plates are rho(x/s).
  • #1
chingcx
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Homework Statement



This is from Prob. 2.25
Two point charges with separation d, P is a point at a distance z above the mid-point of the charges.
The last sentence asked if one of the positive charges is changed to a negative one, what is the potential at P? What field does it suggest? Explain the discrepancy.

Homework Equations


E = -grad V

The Attempt at a Solution


V=0 obviously
E = -grad V = 0
What is the reason behind that gives this result?
 
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  • #2
Remember, [itex]-\vec{\nabla}V=\frac{\partial V}{\partial x}\hat{x}+\frac{\partial V}{\partial y}\hat{y}+\frac{\partial V}{\partial z}\hat{z}[/itex] Since you only know V on the z-axis, you cannot possibly calculate [itex]\frac{\partial V}{\partial x}[/itex] and [itex]\frac{\partial V}{\partial y}}[/itex]. Clearly, any E-field will point in the x-direction, and so it is necessary to determine V(x,y,z) at points off of the z-axis to find [itex]\frac{\partial V}{\partial x}[/itex] and hence E.
 
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  • #3
I had exactly the same question and I kind of understand what you are saying but since V is scalar and E is vector, isn't V supposed to possesses all the information that the three components of E possess? Would you please suggest me how you would compute E = -[tex]\nabla V [/tex] in this case and compare it with calculation using Gauss's Law?

Thanks
 
  • #4
The equation [itex]\vec{E}=-\vec{\nabla}V[/itex] applies to V(x,y,z) (in Cartesian coordinates anyways). The potential you've calculated is actually V(0,0,z) (the -potential on the z-axis) and so you do not know how V varies with x or y, and you cannot use V(0,0,z) to compute E. If you wanted to compute E from the potential, then you would need to find the potential at a general point (x,y,z) (or even just a point on the x-axis in this case) first and use that potential.

In some cases, you know from symmetry that E points in the z direction and so knowing the functional dependence of V(z) is enough. In this case however, E points in the x direction and so you need to know the functional dependence of V(x).
 
  • #5
Thanks,

I also have another question...
Two infinite parallel plates separated by a distance s are at potential 0 and V_0
a) Use Poisson's eqn to find potential V in the region between the plates where the space charge density is rho = rho_0(x/s). The distance x is measured from the plate at 0 potential.
b)What are the charge densities in the plate?

For this problem, I started with number of ways but none of them seem to be working.
 
  • #6
You should start a new thread for that problem.
 

1. What is the difference between electric potential and electric potential energy?

The electric potential at a point in space is a scalar quantity that represents the amount of electric potential energy per unit charge at that point. In other words, it is a measure of the strength of the electric field at that point. Electric potential energy, on the other hand, is the energy that a charge possesses due to its position in an electric field.

2. How is electric potential related to electric field?

The electric field at a point in space is defined as the force per unit charge that would be experienced by a test charge placed at that point. The electric potential at that point is then given by the negative integral of the electric field along a path from a reference point to the point in question. In other words, it is the change in electric potential energy per unit charge as the test charge moves through the electric field.

3. Can electric potential be negative?

Yes, electric potential can be negative. This simply means that the direction of the electric field is opposite to the direction of the force that a positive test charge would experience. In other words, the electric potential decreases as the test charge moves in the direction of the electric field.

4. What is the significance of electric potential in circuit analysis?

In circuit analysis, electric potential plays a crucial role in understanding the behavior of electric circuits. By calculating the electric potential at different points in a circuit, we can determine the direction of current flow and the voltage drops across different components. This information is essential for designing and troubleshooting circuits.

5. How does the concept of electric potential apply to point charges?

The concept of electric potential also applies to point charges. The electric potential at a point in space due to a point charge is given by the Coulomb's law equation, which is the product of the charge and the inverse of the distance between the two points. The electric potential decreases as the distance from the point charge increases, similar to how the electric field decreases with distance.

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