Why Is the Calculated Force Excessive for Lifting the Barbell?

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The discussion revolves around an athlete lifting a 470 N barbell with an initial mass of 86.5 kg, raising it 0.50 m in 2 seconds. The original poster calculated the total force exerted on the feet and derived an acceleration of 25 m/s², which was questioned due to its inconsistency with the distance covered. Another participant pointed out that this calculated acceleration exceeds the acceleration due to gravity, suggesting a misunderstanding of the problem. Clarification is sought regarding whether the athlete's center of mass also rises during the lift. The conversation highlights the need for accurate calculations and understanding of physics principles in weightlifting scenarios.
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An athlete whose mass is 86.5 kg is performing weight-lifting exercises. Starting from the rest position, he lifts, with constant acceleration, a barbell that weighs 470 N. He lifts the barbell a distance of 0.50 m in a time of 2.0 s.


I cannot seem to find the answer to this. This is what i did:

- I found the total force exerted on the feet by doing: 86.5*9.8 + 470N = 1317.7N
- Then I used d = a*t^2 and got that the acceleration is 25m/s^2
- Then i found the mass of the barbell by doing 470N/9.8 and got 47.96kg.
- After using F=ma i added the two forces and got the answer 2516.7N.

This isn't the right answer. What did i do wrong? Any help is appreciated.

Thanks.
 
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hi treyh! :smile:
treyh said:
An athlete whose mass is 86.5 kg is performing weight-lifting exercises. Starting from the rest position, he lifts, with constant acceleration, a barbell that weighs 470 N. He lifts the barbell a distance of 0.50 m in a time of 2.0 s.

i don't understand the question :redface:

is his body remaining stationary (apart from his arms)?

or is his centre of mass also moving up 0.50 m ? :confused:
 
treyh said:
An athlete whose mass is 86.5 kg is performing weight-lifting exercises. Starting from the rest position, he lifts, with constant acceleration, a barbell that weighs 470 N. He lifts the barbell a distance of 0.50 m in a time of 2.0 s.


I cannot seem to find the answer to this. This is what i did:

- I found the total force exerted on the feet by doing: 86.5*9.8 + 470N = 1317.7N
- Then I used d = a*t^2 and got that the acceleration is 25m/s^2
- Then i found the mass of the barbell by doing 470N/9.8 and got 47.96kg.
- After using F=ma i added the two forces and got the answer 2516.7N.

This isn't the right answer. What did i do wrong? Any help is appreciated.

Thanks.

I just read the original post very carefully, but the only question mark I found was at the end of " What did I do wrong?"

I am tempted to reply: " You didn't ask a question?"

The line I highlighted red above is interesting. If an object falls under the influence of gravity - with an acceleration a little under 10 m/s^2 - it covers just under 20m in 2 seconds. This barbell covered only 0.5 m in 2 seconds yet you said the acceleration was 25 m/s^2 - more than double the acceleration due to gravity ??
 
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