Deriving the Rotation Matrix of a Beam Element

dirk_mec1
Messages
755
Reaction score
13

Homework Statement



The rotation matrix below describes a beam element which is rotated around three axes x,y and z. Derive the rotation matrix.

http://img194.imageshack.us/img194/3351/60039512.png

http://img808.imageshack.us/img808/159/64794596.png

Homework Equations


-

The Attempt at a Solution


I can see where the x-values (CXx CYx CZx) come from. They're just the projections of the rotated x-axes (the one with rotation alpha and beta). But I don't understand how the rest is derived can somebody help me?
 
Last edited by a moderator:
Physics news on Phys.org
Rotation about the x-axis through angle \alpha is given by the matrix
\begin{bmatrix}1 & 0 & 0 \\ 0 & cos(\alpha) & -sin(\alpha) \\ 0 & sin(\alpha) & cos(\alpha)\end{bmatrix}

Rotation about the y-axis through angle \beta is given by the matrix
\begin{bmatrix}cos(\beta) & 0 & -sin(\beta) \\ 0 & 1 & 0 \\ sin(\beta) & 0 & cos(\beta)\end{bmatrix}

Rotation about the z-axis through angle \gamma is given by the matrix
\begin{bmatrix} cos(\gamma) & -sin(\gamma) & 0 \\ sin(\gamma) & cos(\gamma) & 0 \\ 0 & 0 & 1\end{bmatrix}

The result of all those rotations is the product of those matrices. Be sure to multiply in the correct order.
 
I suspect that there's a minus sign somewhere wrongly placed in your matrices Halls, am I correct? I moved the minus sign in your second matrix to the lower sine but there's still something wrong for this is my result:

Code:
[                        cos(a)cos(b),               -sin(b),                           cos(b)sin(a)                ]
[ sin(a)sin(c) + cos(a)cos(c)sin(b)         cos(b)cos(c)         cos(c)*sin(a)sin(b) - cos(a)sin(c) ]
[ cos(a)sin(b)sin(c) - cos(c)sin(a)        cos(b)*sin(c)     cos(a)cos(c) + sin(a)sin(b)sin(c)       ]
 
Last edited:
No, all of the minus signs are correctly placed. I am, of course, assuming that a positive angle gives a rotation "counterclockwise" looking at the plane from "above"- from the positive axis of rotation.
 
dirk_mec1 said:

Homework Statement



The rotation matrix below describes a beam element which is rotated around three axes x,y and z. Derive the rotation matrix.

http://img194.imageshack.us/img194/3351/60039512.png

Look at your diagram. Are all of those rotations positive by the right hand thumb rule? (Hint: The answer is no.)
 
Last edited by a moderator:
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top