How Does Piston Movement Affect Pressure in a Closed System?

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In a closed system with a piston pump, the pressure change can be calculated using the formula P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the pressure and volume after the piston moves. While it is noted that temperature changes occur during compression, it is argued that these changes are negligible for the purpose of this calculation, particularly if no heat is supplied. However, air does heat up during compression, which is relevant for adiabatic processes, and the specific relationship for air is T·V^(γ-1) = constant, where γ = 7/5. The discussion emphasizes that without knowing the relative volumes of the piston positions, the significance of temperature change cannot be accurately assessed. Understanding these dynamics is crucial for predicting pressure changes in such systems.
BuddyJim
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Hi,

I have a closed system of fixed volume with an piston pump attached. The medium is air and the initial environmental condition are at standard atmospheric. I would like to know the formulas to use that would provide me with the new pressure when the piston is at top dead center (i.e. traveled a full stroke). Would I be correct in assuming that temperature is negligible when no heat (or fuel) is supplied to the system during the cycle?

Thanks
 
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If you know the initial volume and pressure, you would use P1V1=P2V2, where P1 and V1 are the initial pressure and volume and the other side of the equation is the pressure and volume after the piston has moved.

I would also say that temperature is negligible. It would change slightly, but it's not relevant because it's a result of the pressure change.
 
aroc91 said:
If you know the initial volume and pressure, you would use P1V1=P2V2, where P1 and V1 are the initial pressure and volume and the other side of the equation is the pressure and volume after the piston has moved.

I would also say that temperature is negligible. It would change slightly, but it's not relevant because it's a result of the pressure change.
Actually, air heats up as it is compressed, like in a diesel engine. Specifically for adiabatic compression, T·V γ-1 = constant, where γ = 7/5 for air. There is a similar relation for the pressure increase. See http://en.wikipedia.org/wiki/Adiabatic_process
 
Bob S said:
Actually, air heats up as it is compressed, like in a diesel engine. Specifically for adiabatic compression, T·V γ-1 = constant, where γ = 7/5 for air. There is a similar relation for the pressure increase. See http://en.wikipedia.org/wiki/Adiabatic_process


I know. I just meant that, from the description of the problem, temperature wasn't relevant, not that didn't occur.
 
aroc91 said:
If you know the initial volume and pressure, you would use P1V1=P2V2, where P1 and V1 are the initial pressure and volume and the other side of the equation is the pressure and volume after the piston has moved.

I would also say that temperature is negligible. It would change slightly, but it's not relevant because it's a result of the pressure change.

We can't say whether the temperature change is 'slight' unless we know the relative volumes between piston down and piston up, which the OP failed to mention.
 
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