Vector Identity (del operator)

[racnna]

i am completely lost as to how to go from
p^ \frac{1}{m}∇p
to
\frac{m}{m+1} ∇p^\frac{m+1}{m}

 

[Muphrid]

In general, the chain rule should tell you that,

\nabla p^a = a p^{a-1} \nabla p

Choose an appropriate value for a and see what happens.

 

[racnna]

oh wow...nice trick