Implications of the statement Acceleration is not relative

  • #151


my_wan said,
Gravity turns this relationship on its head. Note the force felt when accelerating. When on the surface of a gravitational mass, like Earth, the principle of equivalence tells us this weight we feel is the same force we feel when accelerating. Now if you jump off a roof then while accelerating toward the ground you feel no force, effectively weightless. Hence, in your frame of reference you are at rest, i.e., not accelerating, but the Earth is accelerating toward you. Yet everybody in the Universe can agree that your speed is changing, even if not by how much. In this case proper gravity is absolute, while how much gravity and coordinate paths are relative. So in this case gravity is absolute, but the coordinate acceleration due to gravity is relative.

I take it that the bold text above is what harrylin refers to as the modern argument...

harrylin said:
Thanks for bringing that up, as it is exactly that modern argument that 1916GR denies; and I had the impression that GregAshmore noticed that point, that it's basically that issue that he discovered. Einstein tried to relativise acceleration by relativising gravitation, so that it's a matter of free opinion if a rocket accelerates or not. Nowadays few people accept that view.

That argument fails in the first version by Langevin, see my earlier remarks as well as elaborations by others.
No, I was not disagreeing with Einstein's contention that it is a matter of free opinion as to whether the rocket accelerates or not.

My understanding is that, even according to modern ideas, it is indeed a matter of free opinion as to whether the rocket accelerates--if one considers acceleration in the usual sense of "rate of change in velocity as measured with respect to a set of coordinates". The statement was, "Coordinate acceleration is relative". (Edit to clarify.)

It is proper acceleration which is absolute; but one may be at rest in a coordinate system while experiencing proper acceleration.

There is at least one person in the universe who will disagree with the claim that the rocket is accelerating: the observer in the rocket who is convinced that he is at rest. (This, I think, is along the lines of another comment on the claim, posted by someone else.)

Still, I don't know anything about how the dynamics of the "resting while accelerating rocket" work, so I'm not making any statement of my own opinion on this issue. I'm only giving my understanding of what I have been told.
 
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  • #152


GregAshmore said:
My understanding is that, even according to modern ideas, it is indeed a matter of free opinion as to whether the rocket accelerates--if one considers acceleration in the usual sense of "rate of change in velocity as measured with respect to a set of coordinates". The statement was, "Coordinate acceleration is relative". (Edit to clarify.)
Yes.

GregAshmore said:
It is proper acceleration which is absolute; but one may be at rest in a coordinate system while experiencing proper acceleration.
Correct.

GregAshmore said:
There is at least one person in the universe who will disagree with the claim that the rocket is accelerating: the observer in the rocket who is convinced that he is at rest. (This, I think, is along the lines of another comment on the claim, posted by someone else.)
It seems like you get the distinction between coordinate and proper acceleration.
 
  • #153


GregAshmore said:
[..] As I recall, someone defined proper acceleration as the derivative of proper velocity with respect to proper time. I don't understand how there can be proper velocity at all, because proper time is the elapsed time at "the same place". If position never changes with respect to time, it would seem that proper velocity must be zero. I did not say anything about it because my objection was much more basic than that, and I figured there would be a logical explanation for it if and when I get that far.
I somewhat agree with that; I quickly looked around for definitions and if I see it correctly the definition by Smoot of "proper acceleration" relates to the coordinate acceleration with respect to an instantaneously co-moving inertial frame (thus there is a change of velocity from zero to non-zero) and that makes sense to me.
In contrast, for me the definition of "proper acceleration" as given in Wikipedia is a misnomer for what I would call apparent gravitation. - http://en.wikipedia.org/wiki/Proper_acceleration
It may be that such different definitions bugged you (they did bug me in earlier discussions).
 
  • #154


GregAshmore said:
I struggled with the issue of whether the rocket is at rest throughout, or not. Part of the struggle has to do with the definition of "frame". If one defines frame to be an inertial frame, the rocket is not at rest while accelerating, while changing inertial frames. However, if one recognizes non-inertial frames, then the rocket is at rest throughout.
Of course it's always possible to be at rest relative to oneself and to define non-inertial reference frames and coordinate systems. However such a reference frame isn't what is implied with "at rest" in the context of SR, which relates the physics to inertial frames: you have remarked that yourself. And saying that something is in rest in a frame in which we define it to be in rest ("the rocket is at rest in its non-inertial frame") is simply meaningless.
[..] I don't say that I fully understand the concept of "absolute proper acceleration" being compatible with "no absolute space".
Not sure to parse that correctly; some of the text of Langevin that I omitted argues for absolute space. That's a matter of opinion.
[..] it could be shown, using the spacetime diagram that is already under consideration, that the rocket is at rest throughout the episode.
Once more, "at rest" in SR normally means at rest in an inertial coordinate system that one chooses as "rest system". In no SR space diagram is the rocket continuously "at rest", because it is moving during part of the voyage no matter which inertial system one chooses as "rest" system.
 
  • #155


GregAshmore said:
ghwellsjr said:
GregAshmore said:
There is only one way to construct the spacetime diagram, due to the unique non-inertial behavior of the rocket.
I don't know why you would say this. Are you referring to the Earth's inertial rest frame? There are an infinite number of ways to construct spacetime diagrams for your scenario, all with different velocities with respect to each other and all just as valid and all producing the same final clock readings and the same things that each observer actually sees.
I was too general in my wording. I only meant that Events A, B, and C have been placed, there is only one way to place Event D.
Actually, Event B is of no consequence in the definition of your scenario. As long as we know the rocket's speed and where (or when) it turns around, that defines the end point.

However, I'd like you to consider an issue related to the one you just raised here and that is, how does the rocket know when to turn around? The rocket cannot know from any direct measurement when the Earth has traveled 10 units away in the rocket frame. That distance is the difference between the spatial components of Event B and C which are simultaneous in the Earth frame but which have a distance between them of 16.67 in the rocket frame. Even if the rocket had instant access to the remote information, it would still have to do some calculation if it's based on distance to determine when to fire its rockets.

To me, a much cleaner way to specify the Twin Paradox is to state the Proper Time on the traveler's clock when he should fire the rockets to turn around. This has the advantage that it doesn't require the specification of any reference frame. In fact, it doesn't even require fully specifying any events since we don't care about the spatial component. So if we know how long it takes for the traveler to get to the turnaround point and we know how fast he is traveling, those two parameters fully specify the complete Twin Paradox scenario (assuming of course that he is returning at the same speed he left at). I fully explained this in the thread you linked to in your opening post.
 
  • #156


GregAshmore said:
my_wan said, [..]
I take it that the bold text above is what harrylin refers to as the modern argument...
Quite so; with the demotion of pseudo gravitational fields one returns to Langevin's argument that acceleration has "absolute" effects that everyone can observe -even for the case that the accelerometer reading remains zero.
[..]My understanding is that, even according to modern ideas, it is indeed a matter of free opinion as to whether the rocket accelerates--if one considers acceleration in the usual sense of "rate of change in velocity as measured with respect to a set of coordinates". The statement was, "Coordinate acceleration is relative". (Edit to clarify.)

It is proper acceleration which is absolute; but one may be at rest in a coordinate system while experiencing proper acceleration.
One can always choose a coordinate system to be always at rest in; once more, that is meaningless for the physics. However, it is certainly true that proper acceleration (both definitions of it) is quantitatively agreed upon by all. If that's all you wanted to understand, then you have certainly achieved your goal. :smile:
There is at least one person in the universe who will disagree with the claim that the rocket is accelerating: the observer in the rocket who is convinced that he is at rest. (This, I think, is along the lines of another comment on the claim, posted by someone else.) [..]
That person, if indeed he denies to be changing his state of motion, will have to explain the physical causes for the observed effects; and I mistakenly thought that you were contemplating the different physical explanations that are given in the literature. If and when you come to that point, you may want to read earlier comments and references that were provided in this discussion.
 
  • #157


GregAshmore said:
That, by the way, is the objection that I felt was being dismissed--the call for consideration of the case in which the rocket is at rest. If I (now, or finally) understand George correctly, that objection is intentionally dismissed by Taylor and Wheeler. Indeed, when the objection is raised, it could be shown, using the spacetime diagram that is already under consideration, that the rocket is at rest throughout the episode. What the objector wants (or at least, what I wanted) was for the symmetrical diagram to be drawn, because he thinks that this is the only spacetime diagram in which the rocket is at rest.
T&W never consider non-inertial frames or a frame in which the traveler is at rest, at least not when discussing the Twin Paradox. What they are dismissing is the explanation that I gave in post #23 of the thread you linked to in your OP. I considered three Inertial Reference Frames which included different rest states of the two twins. I attempted to show that anyone of them was adequate to explain everything about the scenario, which is pretty much the classic way of explaining the Twin Paradox. But they think they have a better way which involves any observer calculating the spacetime interval between pairs of events. I don't think that helps at all but since they are writing the book, they get to decide when the objectors are happy. But real objectors, like you, remained unhappy.
 
  • #158


harrylin said:
Once more, "at rest" in SR normally means at rest in an inertial coordinate system that one chooses as "rest system". In no SR space diagram is the rocket continuously "at rest", because it is moving during part of the voyage no matter which inertial system one chooses as "rest" system.
True. But no one is claiming that the rocket is at rest in an inertial frame--not even the twin in the rocket. The twin in the rocket feels the unbalanced force of the rocket engine, and he knows (or would know upon reunion) that the twin on Earth feels no such force. Even without the formal definitions of inertial and non-inertial, the rocket twin would recognize that his situation is fundamentally different than that of his twin. Fully aware of that difference, he claims that he is at rest throughout the episode.

I don't see how the claim is disproved by pointing out that the rocket changes inertial frames during the firing of the engine. The change of inertial frames only confirms what everyone knows: the rocket is non-inertial. From the Earth twin's point of view, the rocket is in an inertial frame, accelerates, and comes to rest in another inertial frame. The rocket twin disagrees with this assessment. He can point to the spacetime diagram (which the Earth twin accepts as valid) and show that he remains at rest in his own frame, even while not at rest in anyone inertial frame. To prove the rocket twin wrong, it must either be shown that his frame moved with respect to some absolute position marker, or that the laws of dynamics are violated if he does not move. There is no absolute position marker, and the laws of dynamics are not considered in my analysis. [If these statements are wrong, at least they are not bald statements; I've done my homework. :smile: ]
 
  • #159


ghwellsjr said:
T&W never consider non-inertial frames or a frame in which the traveler is at rest, at least not when discussing the Twin Paradox. What they are dismissing is the explanation that I gave in post #23 of the thread you linked to in your OP. I considered three Inertial Reference Frames which included different rest states of the two twins. I attempted to show that anyone of them was adequate to explain everything about the scenario, which is pretty much the classic way of explaining the Twin Paradox. But they think they have a better way which involves any observer calculating the spacetime interval between pairs of events. I don't think that helps at all but since they are writing the book, they get to decide when the objectors are happy. But real objectors, like you, remained unhappy.
I read that post in its entirety before opening this thread. I didn't catch on to what you were doing because in each of the diagrams the rocket twin is spoken of as moving for part of the trip.

What helped me was to realize that in the typical two-frame spacetime diagram, the world line of an inertial particle shows the particle both as moving and at rest. It is moving in one frame, and at rest in the other frame. Thus, the one spacetime diagram actually shows the case I wanted to see-the case in which the rocket twin considers himself at rest. The symmetrical diagram (which is invalid) is not needed.
 
  • #160


ghwellsjr said:
Actually, Event B is of no consequence in the definition of your scenario. As long as we know the rocket's speed and where (or when) it turns around, that defines the end point.
It would be of consequence for the person who mistakenly believes that because either object can be the one that appears to turn around, the spacetime diagram can be drawn with either object having the bent worldline. Event B is where the Earth would turn around. I chose to show at this juncture that the Earth cannot change inertial frames because it experiences no unbalanced force; because it is inertial.

ghwellsjr said:
However, I'd like you to consider an issue related to the one you just raised here and that is, how does the rocket know when to turn around? The rocket cannot know from any direct measurement when the Earth has traveled 10 units away in the rocket frame. That distance is the difference between the spatial components of Event B and C which are simultaneous in the Earth frame but which have a distance between them of 16.67 in the rocket frame. Even if the rocket had instant access to the remote information, it would still have to do some calculation if it's based on distance to determine when to fire its rockets.

To me, a much cleaner way to specify the Twin Paradox is to state the Proper Time on the traveler's clock when he should fire the rockets to turn around. This has the advantage that it doesn't require the specification of any reference frame. In fact, it doesn't even require fully specifying any events since we don't care about the spatial component. So if we know how long it takes for the traveler to get to the turnaround point and we know how fast he is traveling, those two parameters fully specify the complete Twin Paradox scenario (assuming of course that he is returning at the same speed he left at). I fully explained this in the thread you linked to in your opening post.
It is a cleaner solution. Yet even now I feel the [vestigial] reflexive urge to tune it out because it says the rocket twin "travels", "turn around", "return". The doubter has been told that in relativity the rocket has the same right to be at rest as the Earth has. Langauge of motion applied to the rocket speaks so loudly that it drowns out the perfectly valid point that is being made.

For perspective, I have read two or three explanations of the twin paradox to my 30+ son. He has some technical training, has a job that requires him to evaluate contractual language. He had exactly my reaction, without me making any comment.
 
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  • #161


harrylin said:
I somewhat agree with that; I quickly looked around for definitions and if I see it correctly the definition by Smoot of "proper acceleration" relates to the coordinate acceleration with respect to an instantaneously co-moving inertial frame (thus there is a change of velocity from zero to non-zero) and that makes sense to me.
In contrast, for me the definition of "proper acceleration" as given in Wikipedia is a misnomer for what I would call apparent gravitation. - http://en.wikipedia.org/wiki/Proper_acceleration
The two definitions are equivalent. The Smoot definition basically just pushes the use of accelerometers one step further. Instead of reading the proper acceleration directly off the accelerometer, you define an inertial frame by strapping accelerometers to your clocks and rods, ensuring that they read 0, and then reading the proper acceleration off the clocks and rods.
 
  • #162


harrylin said:
That person, if indeed he denies to be changing his state of motion, will have to explain the physical causes for the observed effects;
Which he can do quite easily simply by stating the laws of physics in a covariant form and then using any coordinates where his state of motion does not change.
 
  • #163


GregAshmore said:
True. But no one is claiming that the rocket is at rest in an inertial frame--not even the twin in the rocket.
The physical meaning of "in rest" is very well clarified in Einstein's 1918 paper.
The twin in the rocket feels the unbalanced force of the rocket engine, and he knows (or would know upon reunion) that the twin on Earth feels no such force. Even without the formal definitions of inertial and non-inertial, the rocket twin would recognize that his situation is fundamentally different than that of his twin. Fully aware of that difference, he claims that he is at rest throughout the episode.
Once more, that is true for Einstein's example and completely wrong (even in two ways) for Langevin's example. "At rest" in the sense that you adopt here only makes sense in the way Einstein elaborates - and that isn't SR.
The rocket twin [..] can point to the spacetime diagram (which the Earth twin accepts as valid) and show that he remains at rest in his own frame, even while not at rest in anyone inertial frame. To prove the rocket twin wrong, [..]
For a last time, as we've been here twice before: everyone can always claim to be at rest in his own frame; such a statement cannot be disproved. You could just as well state that you're in your own world. That's physically meaningless.
 
  • #164


DaleSpam said:
The two definitions are equivalent. The Smoot definition basically just pushes the use of accelerometers one step further. Instead of reading the proper acceleration directly off the accelerometer, you define an inertial frame by strapping accelerometers to your clocks and rods, ensuring that they read 0, and then reading the proper acceleration off the clocks and rods.
I prefer his definition as he doesn't confound a displacement with a force; and it does make a difference when using it in SR, due to the different definition of "inertial frame" in SR.
 
  • #165


GregAshmore said:
It would be of consequence for the person who mistakenly believes that because either object can be the one that appears to turn around, the spacetime diagram can be drawn with either object having the bent worldline.
What has been repeated here is that either object CANNOT be the one that appears to turn around because all observers MUST agree on which one accelerated, just as the one that accelerated is also the only one to experience a g force as a result.

You are confusing Einstein's term, most probably with respect to the explanation given for the principle of equivalence. IF every agrees on what happened, even if not to what degree, we are by definition talking about an absolute, not relative event. The relative terms of that absolute involve only the quantitative value associated with it. That is the point we are trying to make with the distinction between coordinate acceleration and proper acceleration.
 
  • #166


DaleSpam said:
Which he can do quite easily simply by stating the laws of physics in a covariant form and then using any coordinates where his state of motion does not change.
As I suspect that you also don't copy Einstein's physical explanation, I'm curious to know which physical explanation that you found in the literature you fancy for the moving and faster aging Earth with a stationary rocket (let's stay away from personal ideas). How can the firing of the rocket engine move the rest of the universe while keeping the rocket's state of motion unaffected?
 
  • #167


harrylin said:
it does make a difference when using it in SR, due to the different definition of "inertial frame" in SR.
Any way you can determine if your frame is inertial or not is a way of determining your proper acceleration, i.e. it is an accelerometer. You cannot get away from using accelerometers.
 
  • #168


DaleSpam said:
Any way you can determine if your frame is inertial or not is a way of determining your proper acceleration, i.e. it is an accelerometer. You cannot get away from using accelerometers.
We have discussed that before, and I found that your definition of "inertial frame" is at odds with that of classical mechanics wrt which SR is defined; as a matter of fact, it's already at odds with Einstein's 1905 paper and Langevin's 1911 paper. So, let's agree to disagree; but if you even disagree to agree to disagree, then I'll just add some links to earlier discussions later, as IMHO everything has been said already.

ADDENDUM: see
https://www.physicsforums.com/showthread.php?p=4117808
In post #190 I provided three operational ways with which such reference frames can be defined/determined.
See also post #200 there and a 4th defintion (by Einstein) in post #264:
https://www.physicsforums.com/showpost.php?p=4122201&postcount=264
 
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  • #169


my_wan said:
What has been repeated here is that either object CANNOT be the one that appears to turn around because all observers MUST agree on which one accelerated
The phrase "appears to turn around" (emphasis added) seems to refer to coordinate acceleration, in which case it would not be true that all observers must agree on it. If you intended the statement to refer to proper acceleration then it is a little confusing.

I think that GregAshmore understands the distinction between coordinate and proper acceleration, so I think that the rest is just miscommunication about which "flavor" of acceleration is being discussed at anyone moment.
 
  • #170


harrylin said:
We have discussed that before, and I found that your definition of "inertial frame" is at odds with that of classical mechanics; as a matter of fact, it's already at odds with Einstein's 1905 paper and Langevin's 1911 paper. So, let's agree to disagree; but if you even disagree to agree to disagree, then I'll just add some links to earlier discussions later.
Some links would help. I don't remember that discussion.
 
  • #171


harrylin said:
As I suspect that you also don't copy Einstein's physical explanation,
Physical explanation of what? You never clarified exactly what you thought he meant by "gravitational field", and he wasn't explicit about it. Until you have defined your terms you are just giving physical explanations of flubnubitz.

harrylin said:
I'm curious to know which physical explanation that you found in the literature you fancy for the moving and faster aging Earth with a stationary rocket (let's stay away from personal ideas). How can the firing of the rocket engine move the rest of the universe while keeping the rocket's state of motion unaffected?
The firing of the rocket engine doesn't move the rest of the universe, the choice of coordinates does. The state of motion or rest is a coordinate-dependent quantity. Do you disagree that I can give any object any velocity profile I like simply by choosing the coordinates appropriately?
 
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  • #172


harrylin said:
We have discussed that before, and I found that your definition of "inertial frame" is at odds with that of classical mechanics wrt which SR is defined

What Einstein said by way of defining inertial frame was in his 1905 paper:
Let us take a system of co-ordinates in which the equations of Newtonian mechanics hold good.

Presumably, since he is suggesting a modification to Newtonian mechanics, he means "approximately", in the low-velocity limit.

The way I interpreted Einstein's words are that an inertial coordinate system satisfies:
  1. Objects that are not acted upon by physical, external forces travel so that \dfrac{d^2 x}{dt^2} = \dfrac{d^2 y}{dt^2} = \dfrac{d^2 z}{dt^2} = 0
  2. For objects moving slowly compared with the speed of light, the response of an object to a physical external force \vec{F} is given (approximately, ignoring correction terms of order \dfrac{v^2}{c^2}) by F^i = m \dfrac{d^2 x^i}{dt^2}
  3. If an object exerts a force \vec{F} on a second object, then the second object exerts a force -\vec{F} on the first.

These conditions characterize an inertial Cartesian coordinate system. They imply that an accelerometer at rest in that coordinate system will show no acceleration. But the other way around may not be true. An accelerometer at rest showing no acceleration doesn't imply that your coordinate system is an inertial Cartesian coordinate system.
 
  • #173


GregAshmore said:
ghwellsjr said:
T&W never consider non-inertial frames or a frame in which the traveler is at rest, at least not when discussing the Twin Paradox. What they are dismissing is the explanation that I gave in post #23 of the thread you linked to in your OP. I considered three Inertial Reference Frames which included different rest states of the two twins. I attempted to show that anyone of them was adequate to explain everything about the scenario, which is pretty much the classic way of explaining the Twin Paradox. But they think they have a better way which involves any observer calculating the spacetime interval between pairs of events. I don't think that helps at all but since they are writing the book, they get to decide when the objectors are happy. But real objectors, like you, remained unhappy.
I read that post in its entirety before opening this thread. I didn't catch on to what you were doing because in each of the diagrams the rocket twin is spoken of as moving for part of the trip.

What helped me was to realize that in the typical two-frame spacetime diagram, the world line of an inertial particle shows the particle both as moving and at rest. It is moving in one frame, and at rest in the other frame.
So because my spacetime diagrams only show one frame instead of the two that are more commonly shown in a Minkowski diagram, that prevented you from grasping what I was presenting, correct? But now that you realize the difference, does post #23 make perfect sense to you? Could you use it with further explanation to get your son to understand what I was presenting there?
GregAshmore said:
Thus, the one spacetime diagram actually shows the case I wanted to see-the case in which the rocket twin considers himself at rest.
Are you talking about this one spacetime diagram?

attachment.php?attachmentid=55868&stc=1&d=1361182733.png


If so, wouldn't it have been just as confusing to you if you had not previously figured out that it was not a conventional Minkowski diagram with two frames in it?
GregAshmore said:
The symmetrical diagram (which is invalid) is not needed.
What are you calling a symmetrical diagram? A Minkowski diagram? And why would it be invalid? And why is it not needed? Now I'm confused.
 
  • #174


GregAshmore said:
ghwellsjr said:
Actually, Event B is of no consequence in the definition of your scenario. As long as we know the rocket's speed and where (or when) it turns around, that defines the end point.
It would be of consequence for the person who mistakenly believes that because either object can be the one that appears to turn around, the spacetime diagram can be drawn with either object having the bent worldline. Event B is where the Earth would turn around. I chose to show at this juncture that the Earth cannot change inertial frames because it experiences no unbalanced force; because it is inertial.
But when I drew the (non-inertial) spacetime diagram showing the Earth as the object that turns around, it doesn't happen at Event B, it happens at two other events. The Earth's bent worldline has two bends in it, not just one.
GregAshmore said:
ghwellsjr said:
However, I'd like you to consider an issue related to the one you just raised here and that is, how does the rocket know when to turn around? The rocket cannot know from any direct measurement when the Earth has traveled 10 units away in the rocket frame. That distance is the difference between the spatial components of Event B and C which are simultaneous in the Earth frame but which have a distance between them of 16.67 in the rocket frame. Even if the rocket had instant access to the remote information, it would still have to do some calculation if it's based on distance to determine when to fire its rockets.

To me, a much cleaner way to specify the Twin Paradox is to state the Proper Time on the traveler's clock when he should fire the rockets to turn around. This has the advantage that it doesn't require the specification of any reference frame. In fact, it doesn't even require fully specifying any events since we don't care about the spatial component. So if we know how long it takes for the traveler to get to the turnaround point and we know how fast he is traveling, those two parameters fully specify the complete Twin Paradox scenario (assuming of course that he is returning at the same speed he left at). I fully explained this in the thread you linked to in your opening post.
It is a cleaner solution.
Please note that I did not say it was a cleaner solution-just a cleaner specification. The cleaner specification does not imply any particular solution or explanation of the Twin Paradox.
GregAshmore said:
Yet even now I feel the [vestigial] reflexive urge to tune it out because it says the rocket twin "travels", "turn around", "return". The doubter has been told that in relativity the rocket has the same right to be at rest as the Earth has. Langauge of motion applied to the rocket speaks so loudly that it drowns out the perfectly valid point that is being made.

Well let's review your entire specification:
GregAshmore said:
Given:
G1. Earth and rocket are both at rest at same position. Earth clock and rocket clock are synchronised.
G2. At time 0.0, rocket fires a pulse.
G3. Earth and rocket separate at relative velocity 0.8c.
G4. At distance 10 units from Earth, as measured in Earth frame, rocket fires a pulse.
G5. Earth and rocket approach at relative velocity -0.8c.
G6. Upon reaching Earth, rocket fires a pulse, coming to rest on Earth.
G7. Gravitational effects of mass are to be ignored.
It's obvious that you are trying to specify the scenario in such a way that it does not imply which object is moving. However, G6 implies that it is the rocket that was moving because you say it comes to rest on Earth. Maybe you should say: At closest approach of Earth and rocket, rocket fires a pulse and once again, both are at rest at the same position.

But there are still problems. Saying that the rocket "fires a pulse" three times throughout the scenario implies that it is exactly the same pulse fired three times in the same direction which, of course, won't work. What could work is if you leave G2 alone and change G3 (using my suggestion) to say: "At time 7.5 according to the rocket's clock, the rocket turns around and fires two pulses" and then at G6 you could say: "At closest approach of Earth and rocket, rocket turns around again and fires a pulse and once again, both are at rest at the same position." If you don't like the term "turns around" then you will have to provide the rocket with thrusters at both ends and state which thruster is being used at each point.
GregAshmore said:
For perspective, I have read two or three explanations of the twin paradox to my 30+ son. He has some technical training, has a job that requires him to evaluate contractual language. He had exactly my reaction, without me making any comment.
I'm all for providing better explanations that actually communicate and maybe we could enlist your son in making that happen. Did he offer any suggestions such as the point you made that my explanation in post #23 was confusing because you expected two frames in one diagram? I can use that suggestion to improve my explanations in the future. More suggestions would be welcome.
 
  • #175


As a side note with regard to my diagrams showing only one frame compared to the more traditional Minkowski diagram showing two frames, let me show you what happened when I tried to make the point that my type of diagram was not a Minkowski diagram:
ghwellsjr said:
By the way, your graphs are not Minkowski diagrams, they are simply conventional position versus time graphs. And I'm not saying that simply because you are interchanging the time versus distance axes that is more common for a Minkowski diagram.
Read the posts following that one and you'll see why I no longer made a distinction between my one-frame spacetime diagrams and the more common two-frame Minkowski diagrams.
 
  • #176


DaleSpam said:
Some links would help. I don't remember that discussion.
Done.
stevendaryl said:
What Einstein said by way of defining inertial frame was in his 1905 paper: [..] Presumably, since he is suggesting a modification to Newtonian mechanics, he means "approximately", in the low-velocity limit. [..]
Indeed, SR is defined wrt the same reference systems as Newton's mechanics.
The way I interpreted Einstein's words are that an inertial coordinate system satisfies:
[*] Objects that are not acted upon by physical, external forces travel so that \dfrac{d^2 x}{dt^2} = \dfrac{d^2 y}{dt^2} = \dfrac{d^2 z}{dt^2} = 0[..]
Not sure if you mean that correctly; a coordinate system of reference is not "objects". For example the surface of the Earth is approximately a valid "Galilean" reference frame (neglecting its rotation and orbit), in which a cannon ball is acted upon by the force of gravity in accordance with Newton's second law. That is a classical textbook example of motion wrt to a valid reference system for classical mechanics, as your second point also stresses:
[*]For objects moving slowly compared with the speed of light, the response of an object to a physical external force \vec{F} is given (approximately, ignoring correction terms of order \dfrac{v^2}{c^2}) by F^i = m \dfrac{d^2 x^i}{dt^2}
[..]
These conditions characterize an inertial Cartesian coordinate system. They imply that an accelerometer at rest in that coordinate system will show no acceleration.
It may however show gravitational force.
But the other way around may not be true. An accelerometer at rest showing no acceleration doesn't imply that your coordinate system is an inertial Cartesian coordinate system.
Right - as illustrated by Langevin. Note that neither he or Einstein would call that "at rest" (without qualifier) in the context of SR.
 
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  • #177


harrylin said:
Not sure if you mean that correctly; a coordinate system of reference is not "objects".

I didn't say otherwise. But the path of an object that is not acted on by any force can be described using a coordinate system, and if that coordinate system happens to be an inertial Cartesian coordinate system, then the path x^i(t) will satisfy

\dfrac{d^2 x^i}{dt^2} = 0

For example the surface of the Earth is approximately a valid "Galilean" reference frame (neglecting its rotation and orbit), in which a cannon ball is acted upon by the force of gravity in accordance with Newton's second law.

I don't see how that contradicts what I said. Of course, if you think of gravity as a force, then you get one inertial coordinate system, and if you don't think of it as a force, then you get a different inertial coordinate system.

That is a classical textbook example of motion wrt to a valid reference system for classical mechanics, as your second point also stresses:

It may however show gravitational force.

So are you saying that whether or not an accelerometer correctly identifies an inertial frame depends on whether you consider gravity to be a force or not?
 
  • #178


DaleSpam said:
Physical explanation of what? You never clarified exactly what you thought he meant by "gravitational field", and he wasn't explicit about it. Until you have defined your terms you are just giving physical explanations of flubnubitz.
It strikes me now that, incredible as this is to me, you actually have no idea what Einstein or his critics were discussing... Basically the whole clock paradox is flubnubitz for you.

I feel like a policeman at a crossroad who shouts at a motorist to stay put - the motorist speeds away and after a chase he's arrested. To his defence the guy states that he stayed put on his bike. and it turns out that he's an English teacher. What to think? Can such a lack of understanding really exist, or is the biker just trying to talk his way out of it by stripping the term from its obviously intended contextual meaning?
The firing of the rocket engine doesn't move the rest of the universe, the choice of coordinates does. The state of motion or rest is a coordinate-dependent quantity. Do you disagree that I can give any object any velocity profile I like simply by choosing the coordinates appropriately?
While I certainly agree with the second sentence, the first one is plain nonsense to me: your choice of coordinates cannot physically move (affect) the universe. "In rest" has in this context the physical meaning that the laws of nature are valid wrt the object; its state of motion is null. Only a force can change its state of motion. We can ascribe a different state of motion to the object by a different choice of reference system; however you can of course not affect my state of motion by changing your choice of coordinates - imaginations of our brains cannot physically affect objects. That is what Einstein clarified as I mentioned to you earlier already in this thread:

To be sure, the accelerated coordinate systems cannot be called upon as real causes for the field, an opinion that a jocular critic saw fit to attribute to me on one occasion.
 
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  • #179


stevendaryl said:
I didn't say otherwise. [..] Of course, if you think of gravity as a force, then you get one inertial coordinate system, and if you don't think of it as a force, then you get a different inertial coordinate system. [..]
Yes indeed, that's what I meant.
So are you saying that whether or not an accelerometer correctly identifies an inertial frame depends on whether you consider gravity to be a force or not?
I gave 4 ways of identifying an inertial frame in SR, incl. how to interpret an accelerometer in that context. Isn't that all very basic, elementary physics??

As this is probably deviating from GregAshmore topic, I'll limit myself to this.
 
  • #180


harrylin said:
ADDENDUM: see
https://www.physicsforums.com/showthread.php?p=4117808
In post #190 I provided three operational ways with which such reference frames can be defined/determined.
See also post #200 there and a 4th defintion (by Einstein) in post #264:
https://www.physicsforums.com/showpost.php?p=4122201&postcount=264
In post #190 the first definition was "Newton defined it as in uniform straight line motion wrt the 'fixed stars'" which of course is a bad definition since the stars aren't fixed (which Newton couldn't have known at the time).

The second definition was "the definition of inertial motion at places far away from massive bodies". Simply being away from massive bodies doesn't give you an inertial frame, so this definition is incomplete and would require something like an accelerometer to complete it.

I didn't see a third definition.

The fourth definition was "coordinate systems relative to which sufficiently isolated, material points move in straight lines and uniformly". That is an equivalent definition to the accelerometer definition. Any way that you can think of determining whether or not a material point is "sufficiently isolated" winds up being an experiment to whether or not its proper acceleration is 0, hence an accelerometer.
 
  • #181


harrylin said:
What to think? Can such a lack of understanding really exist, or is the biker just trying to talk his way out of it by stripping the term from its obviously intended contextual meaning?
So, in your opinion, what is the "gravitational field's" obviously intended contextual meaning? In my opinion, it is the Christoffel symbols, but you seem to have a different opinion that you are strangely secretive about.

harrylin said:
While I certainly agree with the second sentence, the first one is plain nonsense to me
Then you are being logically inconsistent. The second sentence implies the first.

harrylin said:
"In rest" has in this context the physical meaning that the laws of nature are valid wrt the object; its state of motion is null.
Well, this is probably the source of the confusion. You are using terms in non-standard ways. The term "at rest" simply means v=dx/dt=0, and the term "moving" simply means v=dx/dt≠0.

Since the laws of nature can be written in a coordinate independent form they are valid wrt any object, so according to your definition all objects are "in rest".
 
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  • #182


harrylin said:
For this it is sufficient that our traveler consents to be locked in a projectile that would be launched from Earth with a velocity sufficiently close to that of light but lower, which is physically possible, while arranging an encounter with, for example, a star that happens after one year of the traveler's life, and which sends him back to Earth with the same velocity.

Ah, I see that instead of changing the topology of spacetime, Langevin changes its curvature to allow the traveling twin to return without feeling any force. This scenario could not be set up in flat spacetime as he sets it up, because in flat spacetime there is no gravity, so an encounter with a star could not turn the traveling twin around while still having him feel no force.
 
  • #183


DaleSpam said:
The phrase "appears to turn around" (emphasis added) seems to refer to coordinate acceleration, in which case it would not be true that all observers must agree on it. If you intended the statement to refer to proper acceleration then it is a little confusing.

I think that GregAshmore understands the distinction between coordinate and proper acceleration, so I think that the rest is just miscommunication about which "flavor" of acceleration is being discussed at anyone moment.
Correct. I meant coordinate acceleration.
 
  • #184


ghwellsjr said:
So because my spacetime diagrams only show one frame instead of the two that are more commonly shown in a Minkowski diagram, that prevented you from grasping what I was presenting, correct? But now that you realize the difference, does post #23 make perfect sense to you? Could you use it with further explanation to get your son to understand what I was presenting there?
No, it was not that only one frame was shown. It was the description of the rocket as moving. The application of motion words to the rocket is a trigger. The objector is under the mistaken impression that if the rocket does not move, the traveling Earth twin will be younger on reunion. All talk about inertial vs. non-inertial is not exactly denied; it is just ineffective. He feels he is entitled to a review of the case in which the rocket is stationary; he wants to see how it works out. Any description of the rocket as moving triggers the rejection of the explanation and the repeat of the objection: I want to see the case in which the rocket is stationary.

It is difficult to avoid motion words. As you observed, I tried to use neutral descriptors, so that I did not give the reader any room to infer that one or the other object is "really" moving. And, as you also observed, I did not fully succeed. I will revise the text, because I think it is important, in this problem more than others, to avoid the "motion" trigger.

ghwellsjr said:
Are you talking about this one spacetime diagram?
No, I mean the ordinary spacetime diagram, the one showing the Earth's worldline as a single line segment, and the rocket's worldline as two line segments, forming a triangle.

The "aha" moment for me was the realization that this spacetime diagram shows both cases at once. The worldline of the Earth shows the Earth at rest in its inertial frame; that same worldline shows the Earth moving relative to the rocket's inertial frames. Similarly, the two worldlines of the rocket show the rocket in motion with respect to the Earth's inertial frame, and at rest in its two inertial frames.

So, when the objector says, "I want to see the case in which the rocket is at rest", the response can be, "We have that case already in front of us, in the spacetime diagram that we have been studying."

This will come as a surprise to the objector. He believes that the only way to show the rocket at rest is with one line segment.

Having gotten his attention, it can now be shown that the rocket is indeed at rest in its inertial frame during separation, just as the Earth is at rest in its inertial frame.

When the separation ends and approach begins, a choice must be made. One or the other object must change frames. It would be helpful, I think, to show provisionally the Earth changing frames, with the worldline drawn to the "northeast" to meet the rocket, which continues along its original line. This is where the inertial/non-inertial distinction becomes meaningful to the objector. It can be pointed out that Earth is (or would be) at rest in this new inertial frame, just as it was in the original inertial frame. But the Earth cannot change inertial frames, because it is inertial throughout--the Earth twin feels no unbalanced force.

The rocket does feel an unbalanced force; it is non-inertial. It can therefore change inertial frames. But it does not move in its frame, even during the period of "non-inertiality"; its coordinate is zero throughout.

Now the objector (this one, at least) has not only seen the case of the stationary rocket, he understands why the inertial/non-inertial distinction proves that the rocket twin must be younger, and the Earth twin cannot be younger.

ghwellsjr said:
attachment.php?attachmentid=55868&stc=1&d=1361182733.png

If so, wouldn't it have been just as confusing to you if you had not previously figured out that it was not a conventional Minkowski diagram with two frames in it?
The drawing was confusing, but not because it has only one frame. (Arguably it has four, though without axes shown for two?) It is not clear why the Earth's worldline has three segments. Also, it is not obvious why the timing of received light signals is important to the argument. I don't doubt that these issues go away if your explanation is studied with due diligence. It's just that by the time I got that far (in the first reading), I was already overloaded with detail, and fighting the "motion trigger" reflex.

ghwellsjr said:
What are you calling a symmetrical diagram? A Minkowski diagram? And why would it be invalid? And why is it not needed? Now I'm confused.
Consider the valid triangular spacetime diagram: the Earth's single-segment worldline is drawn vertically; the rocket's bent worldline is on the right. The symmetrical diagram has the rocket's worldline drawn vertically, and the Earth's bent worldline on the left. That is the diagram the objector expects to see in the case that the rocket is stationary. It is invalid because the Earth in inertial. It is not needed because the valid diagram shows the case of the rocket at rest.
 
  • #185


DaleSpam said:
The phrase "appears to turn around" (emphasis added) seems to refer to coordinate acceleration, in which case it would not be true that all observers must agree on it. If you intended the statement to refer to proper acceleration then it is a little confusing.
The term "appears" was in effect quoted from GregAshmore post stating "either object can be the one that appears to turn around". In essence I was objecting to the same thing you are here.

DaleSpam said:
I think that GregAshmore understands the distinction between coordinate and proper acceleration, so I think that the rest is just miscommunication about which "flavor" of acceleration is being discussed at anyone moment.
That's what I thought to, but still not sure why previous responses have not resolved the issue.
 
  • #186


harrylin said:
For a last time, as we've been here twice before: everyone can always claim to be at rest in his own frame
Yes. That is the practical meaning of the principal of relativity. "I am at rest. At rest in this position, I will deduce from observation the laws of physics. Those laws will be of the same form as the laws developed by all other resting observers, no matter the type of their motion with respect to me." {Edit: I made a statement similar to this a week or so ago. I seem to remember it was corrected. I'll stand by the gist of it, even if it is not correct in every technical particular. I could look up Einstein's exact words for GR, but I don't think it necessary to make my point.}

harrylin said:
such a statement cannot be disproved.
Of course it can. Show that I have moved with respect to an absolute position marker, and you have disproved the claim. Show that the claim violates a law of physics, and you have disproved the claim. For example, the claim that the rocket is at rest requires some cause for the Earth's coordinate acceleration, its reversal of motion. If there is no cause, then the claim that the rocket is at rest is proven wrong. You yourself have argued against the claim that the rocket is at rest in its non-inertial frame on the grounds that a change of coordinates alone cannot cause the reversal of the earth.

harrylin said:
You could just as well state that you're in your own world. That's physically meaningless.
See above.
 
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  • #187


GregAshmore said:
For example, the claim that the rocket is at rest requires some cause for the Earth's coordinate acceleration, its reversal of motion. If there is no cause, then the claim that the rocket is at rest is proven wrong. You yourself have argued against the claim that the rocket is at rest in its non-inertial frame on the grounds that a change of coordinates alone cannot cause the reversal of the earth.
Why not? The change of coordinates causes coordinate acceleration and reverses the coordinate velocity of the earth. What is in the least bit objectionable about any of that?
 
  • #188


GregAshmore said:
The drawing was confusing, ... It is not clear why the Earth's worldline has three segments. Also, it is not obvious why the timing of received light signals is important to the argument.
Those are both answered here:
http://arxiv.org/abs/gr-qc/0104077

The importance of the timing of the signals is described on page 3 in the section "Radar Time and Radar Distance". The three segments are explained on pages 7 and 8 in the section "Gravity Doesn't Matter".
 
  • #189


DaleSpam said:
Why not? The change of coordinates causes coordinate acceleration and reverses the coordinate velocity of the earth. What is in the least bit objectionable about any of that?
I didn't actually make that argument. (Not in this thread, at least.) Nor do I wish to participate in the argument--it goes against the new rule of me not making statements that I can't verify by calculation.
 
  • #190


GregAshmore said:
I didn't actually make that argument.
My apologies, I got confused with the back and forth.
 
  • #191


GregAshmore said:
Yes. [everyone can always claim to be at rest in his own frame] is the practical meaning of the principal of relativity. "I am at rest.
At rest in this position, I will deduce from observation the laws of physics. Those laws will be of the same form as the laws developed by all other resting observers, no matter the type of their motion with respect to me."
No to your first sentence, yes to your next sentences; obviously this is a matter of careful formulation. One can always design a reference system relative to which one is in rest. That fact is generic (valid for all theories) and has nothing to do with the PoR. The PoR concerns laws of nature.
[..] the claim that the rocket is at rest requires some cause for the Earth's coordinate acceleration, its reversal of motion. If there is no cause, then the claim that the rocket is at rest is proven wrong. You yourself have argued against the claim that the rocket is at rest in its non-inertial frame on the grounds that a change of coordinates alone cannot cause the reversal of the earth.
The rocket is certainly "at rest in its non-inertial frame", but yes you seem to understand what Einstein meant with "in rest". :smile:
 
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  • #192


GregAshmore said:
I want to see the case in which the rocket is stationary.
ghwellsjr said:
Are you talking about this one spacetime diagram?

attachment.php?attachmentid=55868&stc=1&d=1361182733.png

No, I mean the ordinary spacetime diagram, the one showing the Earth's worldline as a single line segment, and the rocket's worldline as two line segments, forming a triangle.
Ok, then are you talking about this spacetime diagram?

attachment.php?attachmentid=55867&stc=1&d=1361182733.png


I thought we agreed that my diagrams show only one frame with Earth as the blue line and the rocket as the red line. So now I need an "aha" moment in order to understand what follows:
GregAshmore said:
The "aha" moment for me was the realization that this spacetime diagram shows both cases at once. The worldline of the Earth shows the Earth at rest in its inertial frame; that same worldline shows the Earth moving relative to the rocket's inertial frames. Similarly, the two worldlines of the rocket show the rocket in motion with respect to the Earth's inertial frame, and at rest in its two inertial frames.

So, when the objector says, "I want to see the case in which the rocket is at rest", the response can be, "We have that case already in front of us, in the spacetime diagram that we have been studying."

This will come as a surprise to the objector. He believes that the only way to show the rocket at rest is with one line segment.
It comes as a surprise to me.
GregAshmore said:
Having gotten his attention, it can now be shown that the rocket is indeed at rest in its inertial frame during separation, just as the Earth is at rest in its inertial frame.

When the separation ends and approach begins, a choice must be made. One or the other object must change frames. It would be helpful, I think, to show provisionally the Earth changing frames, with the worldline drawn to the "northeast" to meet the rocket, which continues along its original line. This is where the inertial/non-inertial distinction becomes meaningful to the objector. It can be pointed out that Earth is (or would be) at rest in this new inertial frame, just as it was in the original inertial frame. But the Earth cannot change inertial frames, because it is inertial throughout--the Earth twin feels no unbalanced force.
Could you please draw the diagrams that you are describing? I'm totally confused.
GregAshmore said:
The rocket does feel an unbalanced force; it is non-inertial. It can therefore change inertial frames. But it does not move in its frame, even during the period of "non-inertiality"; its coordinate is zero throughout.

Now the objector (this one, at least) has not only seen the case of the stationary rocket, he understands why the inertial/non-inertial distinction proves that the rocket twin must be younger, and the Earth twin cannot be younger.
I'm afraid I'm going to become the objector now. I just don't understand your reasoning. Please draw diagrams with annotations so that I can follow your line of reasoning.
GregAshmore said:
The drawing was confusing, but not because it has only one frame. (Arguably it has four, though without axes shown for two?)
My drawings have only one frame--didn't we agree on that? I thought the issue for you had nothing to do with my diagrams not being typical Minkowski diagrams with more than one frame depicted? I'm really confused.
GregAshmore said:
It is not clear why the Earth's worldline has three segments.
It actually has five. I just didn't draw the vertical segments at the top and the bottom where the Earth and the rocket are "at rest at same position". But to understand why there are those three segments for the non-inertial diagram in which the rocket is at rest, read posts #92 and #93 of this thread.
GregAshmore said:
Also, it is not obvious why the timing of received light signals is important to the argument. I don't doubt that these issues go away if your explanation is studied with due diligence. It's just that by the time I got that far (in the first reading), I was already overloaded with detail, and fighting the "motion trigger" reflex.
The timing of those all-important light signals is how the rocket twin creates the spacetime diagram. That is explained in the link in the previous post.

If you don't doubt that these issues go away if you study my explanations, then why haven't you studied them?
GregAshmore said:
Consider the valid triangular spacetime diagram: the Earth's single-segment worldline is drawn vertically; the rocket's bent worldline is on the right. The symmetrical diagram has the rocket's worldline drawn vertically, and the Earth's bent worldline on the left. That is the diagram the objector expects to see in the case that the rocket is stationary. It is invalid because the Earth in inertial. It is not needed because the valid diagram shows the case of the rocket at rest.
If I saw that symmetrical spacetime diagram, I would not understand why you say it is invalid just because the Earth is inertial or why the valid diagram shows the case of the rocket at rest. I don't think a real objector would be persuaded by your arguments, at least I am not.
 
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  • #193


DaleSpam said:
So, in your opinion, what is the "gravitational field's" obviously intended contextual meaning? In my opinion, it is the Christoffel symbols, but you seem to have a different opinion that you are strangely secretive about.
Einstein was a physicist, but you try to interpret his physical explanations mathematically. There is no secret about a field in physics being a zone of influence where a force is exerted by a physical cause; that's the meaning of "field" at the time that Einstein used the term, and he didn't modify its meaning.
[..] Well, this is probably the source of the confusion. You are using terms in non-standard ways. The term "at rest" simply means v=dx/dt=0, and the term "moving" simply means v=dx/dt≠0. Since the laws of nature can be written in a coordinate independent form they are valid wrt any object, so according to your definition all objects are "in rest".
I'll try one last time. Please explain how the Earth can be accelerated with effect back in time due to the firing of the rocket engines. Which law of nature permits that?
 
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  • #194


PeterDonis said:
Ah, I see that instead of changing the topology of spacetime, Langevin changes its curvature to allow the traveling twin to return without feeling any force. This scenario could not be set up in flat spacetime as he sets it up, because in flat spacetime there is no gravity, so an encounter with a star could not turn the traveling twin around while still having him feel no force.
No, in 1911 there was no GR. SR assumes flat spacetime and handles gravitation classically. The mistake that you ascribe to Langevin is due to you projecting modern GR concepts on him teaching SR correctly in 1911.
 
  • #195


harrylin said:
I'll try one last time. Please explain how the Earth can be accelerated with effect back in time due to the firing of the rocket engines. Which law of nature permits that?

The modern way of saying it is that physical effects cannot propagate faster than light, but that coordinate acceleration is not (purely) physical. Coordinates are a system of book-keeping for events, and whether an object has zero or nonzero coordinate acceleration is as much a fact about your coordinate system as it is about the object. The point of introducing the notion of "proper acceleration" is to tease apart what's physical about an object's motion from what's an artifact of your coordinate system.
 
  • #196


harrylin said:
No, in 1911 there was no GR. SR assumes flat spacetime and handles gravitation classically. The mistake that you ascribe to Langevin is due to you projecting modern GR concepts on him teaching SR correctly in 1911.

But SR, together with classical (Newtonian) gravity is inconsistent, I believe.
 
  • #197


harrylin said:
Einstein was a physicist, but you try to interpret his physical explanations mathematically. There is no secret about a field in physics being a zone of influence where a force is exerted by a physical cause; that's the meaning of "field" at the time that Einstein used the term, and he didn't modify its meaning.
Yes, of course. Einstein was an excellent theoretical physicist, so he spent a great deal of time and effort to put his physical explanations into a mathematical framework. So his physical explanations refer to mathematical terms in his physical theory.

The question to you, which you continue to avoid, is which specific mathematical term in Einstein's theory do you think is he talking about when he says "gravitational field"? I think he is talking about the Christoffel symbols. You disagree, so please be explicit.

harrylin said:
I'll try one last time. Please explain how the Earth can be accelerated with effect back in time due to the firing of the rocket engines. Which law of nature permits that?
I really enjoy the hypocrisy of your "I'll try one last time" statement. As though I have been evasive on this point at all. I answered in 109, 114, and most explicitly in 171. However, since I want to foster clear communication, I will repeat the answer again.

It is not the firing of the rocket engine which causes the (coordinate) acceleration of Earth, it is the choice of coordinates. If you used the same coordinates without a rocket then the Earth would (coordinate) accelerate just the same. If you used different coordinates with the rocket then the Earth would not (coordinate) accelerate the same. The (coordinate) acceleration of the Earth therefore depends on the choice of coordinates, and does not depend on the firing of the rocket engines.
 
  • #198


stevendaryl said:
The modern way of saying it is that physical effects cannot propagate faster than light, but that coordinate acceleration is not (purely) physical. Coordinates are a system of book-keeping for events, and whether an object has zero or nonzero coordinate acceleration is as much a fact about your coordinate system as it is about the object. The point of introducing the notion of "proper acceleration" is to tease apart what's physical about an object's motion from what's an artifact of your coordinate system.
Yes, agreed.
 
  • #199


stevendaryl said:
But SR, together with classical (Newtonian) gravity is inconsistent, I believe.
I don't know if it is inconsistent; for sure SR ignores effects from gravitation on time.
Coincidentally the effect of the star's gravitation on the traveler's aging should be quite small in the given example, perhaps less than the effect of Earth's gravitation on that of the stay-at-home. Commonly that is neglected in such examples.
 
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  • #200


DaleSpam said:
[..] The question to you, which you continue to avoid, is which specific mathematical term in Einstein's theory do you think is he talking about when he says "gravitational field"? I think he is talking about the Christoffel symbols. You disagree, so please be explicit.
I disagreed with your assumption that he was discussing mathematical symbols when he wrote "gravitational field"; regretfully all my attempts to clarify the misunderstanding were in vain. I won't try anymore.
I really enjoy the hypocrisy [SNIP]
Enough, that ends our discussions.
 
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