What position does lonepair of electron takes?

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In the discussion, the positioning of lone pairs in molecular geometries is analyzed, specifically in SCl4 and IF5. In SCl4, the lone pair occupies an equatorial position, while in IF5, it occupies an axial position due to its pseudo-octahedral geometry. The distinction between axial and equatorial positions is clarified, noting that five fluoride ligands cannot occupy all six corners of an octahedron, leading to the conclusion that the lone pair occupies the sixth corner, resulting in a pseudo-octahedral configuration. The conversation also touches on the equivalence of the corners in an octahedron, suggesting that there is no inherent difference between axial and equatorial positions.
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In molecules like SCl4 lone pair occupy equitorial position.But, in IF5 lone pair occupy axial position.Why can't the lone pair in SCl4 occupy axial position?
 
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IF5 has a pseudo-octahedral geometry. Can you tell me how to distinguish between axial and equatorial positions in an octahedron?
 
Don't know.I have studied molecular shapes up to octahedral.so excuse me.
 
Five fluoride ligands can't occupy all the six corners of an octahedron, hence the coordination geometry can't be octahedral. But if we take the lone pair into account, it occupies the sixth corner of the octahedron. Therefore we speak of a pseudo-octahedral geometry.
I wanted to say that all the six corners in an octahedron are equivalent, so there is no difference between axial and equatorial.
 
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