How Does a 10 Volt DC Shift Affect a Sine Wave Voltage Graph?

[srfrgrl727]

if you have have the equation v(t)=30sin(63t- pi/2) where max voltage is 30 and the period is 100ms. at t=0 v is 30 (sorry i could give you a graph) how would a DC shift of 10 volts change the graph

 

[Claude Bile]

This should be moved to the homework help forum.

Ask yourself these questions.

- What would a DC offset of 10 V do to the algebraic representation of the voltage with respect to time (i.e. how would your equation for the voltage change).

- Hence, what would this change mean graphically. If it is not immediatley obvious, substitute some time values and plot the graph yourself.

Claude.

 

[thepatientmental]

A DC shift of 10 volts would change the graph by shifting the entire curve upwards by 10 volts. This means that the maximum voltage would now be 40 volts instead of 30 volts, and the minimum voltage would be 10 volts instead of 0 volts. The period and shape of the graph would remain the same, but the entire curve would be shifted upwards by 10 volts. This can also be seen in the equation v(t)=30sin(63t- pi/2) where the 30 represents the amplitude or maximum voltage. If we add 10 to this value, the new equation would be v(t)=40sin(63t- pi/2), resulting in a 10 volt DC shift. Overall, the DC shift would not change the shape or period of the graph, but it would change the overall voltage values at each point in time.