Shannon's Formula c = b log2 (1 + s)

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The discussion focuses on understanding Shannon's formula, specifically the calculation of channel capacity (C) using the equation C = B x log2(1 + S), where B is bandwidth and S is the signal-to-noise ratio (SNR). An example is provided with an SNR of 127 and a bandwidth of 3000 Hz. The correct approach involves adding one to the SNR, resulting in 128, and calculating log2(128), which equals 7. Multiplying this by the bandwidth (3000) yields a channel capacity of 21000 bps. The feedback emphasizes the importance of clearly presenting the logarithmic calculation to avoid confusion, correcting the initial misrepresentation of the logarithmic result.
Radiatedtheory18
im trying to understand shannon's formula for some time now. i have tryed to theorise if this is correct the way i have worked out an example using the formula below.

c = b x log2 (1 + s)

for example

signal to noise ratio 127
b = 3000 b = bandwidth
as shannon's formula states to add one to the signal to noise ratio to make it 128

Log 2 = 27= 128

then we multiply the log2 by the bandwidth to get

21000 Bps

C=BXL

in formula the answer

21000 = 3000 x log2

is that correct?
 
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You get the right answer, but your presentation is confusing. You should state clearly that the log of 128 to the base 2 is 7, and then show the multiplication of that 7 by 3000 to give the answer 21000.

The way you have it now gives a first impression of being wrong.
 
128 = log to the base 2 is 27

7 x 3000 = 21000bps
 
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