Calculate the acceleration due to gravity

AI Thread Summary
To calculate the acceleration due to gravity (ga) at the surface of the rock, the relevant equation is s = ut + 1/2 at², where the initial velocity (u) is zero since the object falls from rest. Given the distance (s) of 2.00 m and the time (t) of 8.0 s, the equation simplifies to 2 = 0 + 1/2 a(8)². Solving for acceleration yields a = 0.0625 m/s². The discussion also addresses significant figures, noting that the final answer should match the precision of the given measurements, which are to three significant figures. The final answer should therefore be reported as 0.0625 m/s².
imy786
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Homework Statement



density, ρ of the rock is 4000 kg m−3 and that this density is uniform throughout. You have equipment that enables you to measure the time it takes for a small object to fall from rest through a distance of 2.00 m. Your measurement is 8.0 s.

(a) Calculate the acceleration due to gravity ga at the surface of the rock.
ga is constant for the drop in the experiment


Homework Equations



t=8
ρ=4000
s=2
a=?

s=ut+1/2 at2

The Attempt at a Solution



well i can't work out the acceleration as i don't know the velocity.
Need help on this...
 
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It says "fall from rest". What does this tell you about the initial velocity?
 
t=8
ρ=4000
s=2
a=?
u=0

s=ut+1/2 at2
2= 32 a
a=0.0625 m/s2
 
Sure, looks fine.
 
to how many significant figues should i give the answer to...
if i have been given time and distance to 3.s.f...should i also give the final answer to s.3.f?
 

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