How Do You Calculate Average Power in an AC Circuit with Phasors?

AI Thread Summary
To calculate average power in an AC circuit using phasors, first express the voltage and current in RMS values, which are 70.7 for voltage and 7.07 for current based on their peak values. The angle difference between the voltage and current phasors is 30 degrees, derived from the given phase angles of 20 degrees and -10 degrees. The average power can be calculated using the formula Pave = (Vm * Im)/2 * cos(theta), where Vm and Im are the RMS values. It's important to remember that the cosine of the angle difference remains the same regardless of the order of subtraction. Understanding these concepts is crucial for accurately calculating average power in AC circuits.
ineedmunchies
Messages
42
Reaction score
0
Ok I've been given a problem that I've got stuck on, I was wondering if anyone here could help.

Q:
v(t) = 100 sin(200t+20^)
i(t) = 10 sin(200t-10^)
Express voltage and current as phasors, and calculate the average power being supplied. (I've used ^ to denote degrees)

The phasors part is pretty simple I think, the voltage is a line 100 in magnitude and 20 degrees positive of the x axis, and the current is of 10 magnitude and 10 degrees negative of the x axis.

phasor.jpg


Its the power bit that I don't get, should I break these down into complex form and multiply them that way?
 
Engineering news on Phys.org
The phasors part is pretty simple I think, the voltage is a line 100 in magnitude and 20 degrees positive of the x axis, and the current is of 10 magnitude and 10 degrees negative of the x axis.

Be careful here. v(t) and i(t) are given in peak values. Phasors are represented in RMS or effective values.

To find ave. power, you need to find the power factor. Which is the cos(theta), where theta is the angle difference between the i(t) and v(t).

Pave = (Vm*Im)/2 * cos(theta)
Where Vm and I am are the peak values of v(t) and i(t), respectively.
 
Oh I forgot about them being in rms, that means they should be .707 times the peak values, because they are sinusoidal?

And theta would be 30 degrees?
 
Oh I forgot about them being in rms, that means they should be .707 times the peak values, because they are sinusoidal?
Correct.
And theta would be 30 degrees?
Correct also.
Dont forget that cosine of a positive and negative theta gives the same result. So it won't matter which angle you subtracted from what.
 
While I was rolling out a shielded cable, a though came to my mind - what happens to the current flow in the cable if there came a short between the wire and the shield in both ends of the cable? For simplicity, lets assume a 1-wire copper wire wrapped in an aluminum shield. The wire and the shield has the same cross section area. There are insulating material between them, and in both ends there is a short between them. My first thought, the total resistance of the cable would be reduced...
Hi all I have some confusion about piezoelectrical sensors combination. If i have three acoustic piezoelectrical sensors (with same receive sensitivity in dB ref V/1uPa) placed at specific distance, these sensors receive acoustic signal from a sound source placed at far field distance (Plane Wave) and from broadside. I receive output of these sensors through individual preamplifiers, add them through hardware like summer circuit adder or in software after digitization and in this way got an...
I am not an electrical engineering student, but a lowly apprentice electrician. I learn both on the job and also take classes for my apprenticeship. I recently wired my first transformer and I understand that the neutral and ground are bonded together in the transformer or in the service. What I don't understand is, if the neutral is a current carrying conductor, which is then bonded to the ground conductor, why does current only flow back to its source and not on the ground path...
Back
Top