Projectile Motion shot over a cliff

AI Thread Summary
A projectile is launched from a 125m high cliff at an initial speed of 105m/s and an angle of 37 degrees. The time taken to hit the ground is calculated to be approximately 5.05 seconds, resulting in a horizontal range of 530 meters from the base of the cliff. To determine the horizontal and vertical components of velocity just before impact, it is suggested to use the time calculated in part a. The discussion references HyperPhysics for additional guidance on projectile motion calculations. The focus remains on completing the analysis of the projectile's velocity components and overall trajectory.
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1. A projectile is shot from the edge of a cliff 125m above ground level with an initial speed of 105m/s at an angle of 37.0 degrees with the horizontal. a) Determine time taken by projectile to hit point P at ground level. b) Determine range X of the projectile as measured from the base of cliff. At the instant just before the projectile hits point P, find c) the horizonal and vertical components of its velocity, d) the magnitude of the velocity, and e) the angle made by the velocity vector with the horizontal.

2. For c, how do you find the vertical/horizontal components? Should I use my answer for a to complete part c?

3. a) t=sqrt(2h/g)=sqrt(2*125m/9.81m/s^2)=5.05 s
b) x=105m/s * 5.05s=530 m

that's all i have so far. i don't know how to start c and the rest after that.
 
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