Bouyency and Water Discplacement of 2 Fluids

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The discussion revolves around calculating the difference in volume between fresh water and salt water displaced by a boat that displaces water weighing 37.3 kN. The buoyant force equation and the relationship between mass, density, and volume are applied to find the volumes of both fluids. The calculation yields a difference of 0.354 m³, but there is uncertainty about its correctness. Participants express agreement with the calculation, suggesting it may be accurate. The conversation highlights the importance of understanding buoyancy and fluid displacement in physics.
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Homework Statement



A boat floating in fresh water displaces water weighing 37.3 kN. What is the difference between the volume of fresh water displaced and the volume of salt water displaced (Vfresh - Vsalt)?

F(bu) = 37.3E3 kg/m^3
(rho)fresh water = .998E3 kg/m^3?
(rho)salt water = 1.10E3 kg/m^3?


Homework Equations



F(bu) = m(of water displaced)g
m(of water displaced) = (rho)V


The Attempt at a Solution



F(bu) = (rho)Vg
V = F(bu)/[(rho)g]
V(f) - V(s) = [F(bu)/(rho)][1/(rhof)-1/(rhos)]
V(f) - V(s) = [37.3E3/9.8][1/(.998E3) - 1/(1.10E3)] = .354m^3

This is wrong?
 
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vMaster0fPuppet said:

Homework Statement



A boat floating in fresh water displaces water weighing 37.3 kN. What is the difference between the volume of fresh water displaced and the volume of salt water displaced (Vfresh - Vsalt)?

F(bu) = 37.3E3 kg/m^3
(rho)fresh water = .998E3 kg/m^3?
(rho)salt water = 1.10E3 kg/m^3?


Homework Equations



F(bu) = m(of water displaced)g
m(of water displaced) = (rho)V


The Attempt at a Solution



F(bu) = (rho)Vg
V = F(bu)/[(rho)g]
V(f) - V(s) = [F(bu)/(rho)][1/(rhof)-1/(rhos)]
V(f) - V(s) = [37.3E3/9.8][1/(.998E3) - 1/(1.10E3)] = .354m^3

This is wrong?

Looks correct to me.

CS
 
me too
 
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