Electric Field at Surface & Inside Thin Hollow Sphere

AI Thread Summary
The discussion focuses on calculating the electric field at the surface and inside a thin hollow sphere with a uniform surface charge density. For part a, it is established that the electric field at the surface is |a|/E0, utilizing Gauss' Law and symmetry principles. In part b, after drilling a tiny hole, the electric field in that hole is shown to be |a|/2E0. This is derived by considering the superposition of the original sphere's field and the field from the hole treated as a negative surface charge. The analysis emphasizes the behavior of electric fields near charged surfaces and the effects of symmetry.
PinkFlamingo
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I'm also stuck on this one. Could someone help me please? :confused:

An insulating, thin, hollow sphere has a uniform surface charge density, a.

a) show that the magnitude of the electric field at the surface of the sphere is |a|/E0 (where E0 is the permittivity of free space)

b) a tiny hole is drilled through the shell, thus removing a negligible but of the charge. Show that the magnitude of the electric field in this hole is |a|/2E0
 
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For part a, consider that the surface of the Earth "looks" flat to us. Alternatively, you can use Gauss' Law and symmetry.

I'd have to think about b for a little bit. I'll leave that to one of the regular helpers here.
 
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