Potential Energy for magnetic dipole

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The potential energy (U) of a magnetic dipole is maximized when the dipole moment is antiparallel to the magnetic field (B) and minimized when they are parallel. This is because the potential energy is defined by the equation U(θ) = μ • B, where the angle θ affects the energy based on the alignment of the dipole and the field. When the dipole moment is perpendicular to B, the potential energy is zero, not maximum, as the torque is indeed maximal in this position, but the energy is a function of alignment. The confusion arises from the relationship between torque and potential energy; while torque is highest at perpendicular alignment, potential energy is lowest. Understanding this distinction clarifies the behavior of magnetic dipoles in magnetic fields.
richard7893
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I am not understanding why the potential energy (U) for a magnetic dipole is at it's maximum when the magnetic dipole moment is antiparallel to the magnetic field (B), why U is at it's minimum when the magnetic dipole moment and B are parallel, and why U is zero when B and the magnetic dipole moment are perpendicular. To me it seems that U would be greatest when the magnetic dipole moment and B are perpendicular because when the dipole is in this position it seems it would have the most potential to rotate (because this is the position in which torque is maximal). And it seems to me U would be zero when the dipole moment is parallel or antiparallel to B because when the dipole is in this position there is no potential for the dipole to rotate, the torque is zero when the dipole is at the positions. I'm having a hard time following the discussion going on in my textbook about this.
 
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