Multi-variable integration with a e^u

MasterWu77
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Homework Statement



Find the mass of the rectangular box B where B is the box determined by
0 \leq x \leq 1, 0 \leq y \leq 2, and 0 \leq z \leq 1, and with density function \rho ( x, y, z ) = z e^{x+y}.

Homework Equations



"u" substitution

The Attempt at a Solution



I believe I've taken the first integral with respect to dz correctly which led me to this integral

\int from 0 to 1 \int from 0 to 2 (1/2)e^(x+y) dy dx

I know i need to use a "u" substitution and have u=x+y but I'm unsure of how that changes the range of the integral with respect to y. if my equation is unclear please let me know. thank you!
 
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write out the triple integral and use
e^{x+y} = e^x e^y
 
ah ok i understand how that works out! thank you! greatly appreciated!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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