Kinetic energy stored in the flyweel

AI Thread Summary
The discussion revolves around calculating the kinetic energy stored in a flywheel for a car, using the given radius, mass, and rotational speed. The initial attempt used the incorrect formula for inertia, leading to an incorrect kinetic energy calculation. The correct formula for inertia is I = 1/2mr^2, which was identified as the source of the error. After correcting the inertia calculation, the kinetic energy can be accurately determined. The importance of using the right equations in physics problems is emphasized.
jeneekim
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Homework Statement



A car is designed to get its energy from a ro-
tating flywheel with a radius of 2.19 m and
a mass of 679 kg. Before a trip, the fly-
wheel is attached to an electric motor, which
brings the flywheel’s rotational speed up to
7310 rev/min.
Find the kinetic energy stored in the fly-
wheel.
Answer in units of J.


Homework Equations



KE = 1/2I\omega2
I = mr2

The Attempt at a Solution



given:
r = 2.19 m
m = 679 kg
\omega = 7310 rev/min = 765.50141 rad/s

I = mr2
= (679 kg)(2.19 m)2
= 3256.5519 kgm2

KE = 1/2I\omega2
= 1/2(3256.5519 kgm2)(765.50141 rad/s)2
= 954157346 J

When I enter this answer, it says that it is incorrect? Could someone please let me know what I'm doing wrong?

Thank you!
 
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I figured it out! I was using the wrong equation for Inertia...it should be:

I = 1/2mr^2
 
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