How Do You Calculate Stopping Distance and Time with Kinetic Friction?

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To calculate stopping distance and time for a car braking from 20 m/s with a coefficient of kinetic friction of 0.1, one can use the principles of energy conservation and the work-energy theorem. The work done by friction equals the change in kinetic energy, allowing for the determination of stopping distance. The book indicates that both distance and time to stop are 200 m and 20 s, respectively. However, there is confusion about how to derive these values from the given information. Clarifying the application of these physics concepts can help solve the problem accurately.
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Homework Statement



1. A car moving at 20 m/s brakes and slides to a stop. If the coefficient of kinetic friction between the pavement and the tires of the car is 0.1, how far does the car slide?

A. 50 m
B. 100 m
C. 200 m
D. 400 m

2. A car moving at 20 m/s brakes and slides to a stop. If the coefficient of kinetic friction between the pavement and the tires of the car is 0.1, how much time is needed for the car to come to a complete stop?

A. 1 s
B. 10 s
C. 20 s
D. 40 s


Homework Equations



U(k)mgcos0

The Attempt at a Solution



Well the answers for both are C, as the back of the book states. The problem is, I don't understand how you can figure out either the time or distance with the information given... can anyone shed some light?
 
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Use energy conservation for the first one, the work done by friction is the change in kinetic energy.
 
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