Find the point on the curve y=√(4x) that is closest the the point (3,0)

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Homework Statement


Find the point on the curve y=√(4x) that is closest the the point (3,0)


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The Attempt at a Solution


I don't even know where to start.
 
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What's the distance between (x,sqrt(4x)) and (3,0)?
 
It wasnt given. The only thing given was the point, and the equation.
 
mg2 said:
It wasnt given. The only thing given was the point, and the equation.

No, no. In general, what's the distance between two points (a,b) and (c,d)? Use a general distance formula. You don't have to be given the formula.
 
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Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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