Finding the Determinant of a 4x4 Matrix with Variable Rows

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Homework Help Overview

The problem involves finding the determinant of a modified 4x4 matrix, where the original matrix has a known determinant of -5. The new matrix's rows are expressed in terms of linear combinations of the original rows.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of determinant properties, particularly linearity, and question the implications of modifying rows through linear combinations.

Discussion Status

The discussion is exploring the properties of determinants, with some participants seeking clarification on linearity and its role in determining the new matrix's determinant. There is an ongoing examination of how changes to the rows affect the determinant.

Contextual Notes

Some participants express confusion regarding the terminology and properties of determinants, indicating a potential gap in foundational knowledge that may affect their understanding of the problem.

ahsanxr
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Homework Statement



The 4x4 matrix with rows v1, v2, v3 and v4 has a determinant of -5. What is the determinant of the matrix with rows v1, v2, 7v3+6v4, 6v3+8v4?

Homework Equations





The Attempt at a Solution



I tried doing -5x7x8=-280 but its saying its wrong. I don't understand why. I'm using the properties of determinants of matrices.
 
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You are using the linearity of determinants, right? What about the contribution from [v1, v2, 6v4, 6v3]?
 
Yes but the property I read was that if a multiple of a row is added to another row, then there is no change to the determinant.
 
ahsanxr said:
Yes but the property I read was that if a multiple of a row is added to another row, then there is no change to the determinant.

True. But you added a multiple of v4 to the third row. That didn't change the determinant, but it did change the third row. Now when you add a multiple of v3 to the fourth row, you can't claim that doesn't change it. Because the third row isn't v3 anymore! Use linearity directly.
 
v3 still remains v3 because it is not defined as the 3rd row of a matrix in general but instead is the specific 3rd row of the original matrix.
 
ahsanxr said:
v3 still remains v3 because it is not defined as the 3rd row of a matrix in general but instead is the specific 3rd row of the original matrix.

That's wrong. I'm not going to argue with you why. Use linearity. Stuff like det[v1,v2,a*v3+b*v4,v4]=det[v1,v2,a*v3,v4]+det[v1,v2,b*v4,v4], and you'll see why your answer is wrong. Apply it to det[v1,v2,a*v3+b*v4,c*v3+d*v4]. There are TWO nonvanishing determinants in the expansion.
 
I don't understand by what you mean by "linearity." I haven't heard of that term. I was taught the properties of determinants but that's it.
 
ahsanxr said:
I don't understand by what you mean by "linearity." I haven't heard of that term. I was taught the properties of determinants but that's it.

Huh. I would have listed linearity first in my list of determinant properties. It's what I tried to sketch in the last post. If a row of a matrix is given by the sum of two vectors A+B, then the resulting determinant is the sum of the determinant of the matrix with the row replaced by A and the determinant of the matrix with the row replaced by B.
 
Oh that was the name of a property. I didn't know that. I got the right answer now. Thanks for your help.
 

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