How Do You Calculate the Volume of Liquid in a Partially Filled Conical Glass?

AI Thread Summary
To calculate the volume of liquid in a partially filled conical glass, one must define the height of the glass (H) and the height of the liquid (h). The volume of a cone is given by the formula V = (1/3)πr²H, where r is the radius at height h. The challenge lies in finding the relationship between the radius and height using similar triangles, which affects the volume calculation. The initial approach led to the incorrect ratio of H:2h, highlighting the need to consider how the radius changes as the height of the liquid changes. Understanding these relationships is crucial for accurately determining the volume of liquid in the cone.
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This is a problem that my lecturer gave us in class and it has been bugging me ever since. I have been unsuccesful in finding or calculating a proper solution so I am hoping PF will be able to help...

This is the Q:

Let H be the height of a conical glass which is filled to a height h. Find the volume of the liquid in the glass as a proportion of the volume if the glass is full. Find the ratio h/H for which the glass is half full.
To answer this question you must construct a mathematical model defining all the variables.

This does not sound like a difficult question to solve but whenever I try to solve with simple conical volume equations I just get that the ratio is H:2h which is obviously not right. Any help would be greatly appreciated.
 
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Why don't you explain how you got H:2h?
 
Well the formula for a volume of a cone is:
V=1/3*pi*r^2*H.

V1 which is the volume of the full cone and V2 is the volume of the half full cone it is clear that V1/2=V2. I put the volume equations into this with the two differnt heights and when the constants are removed (pi, 1/3) you are left with H=2h. ahh but i have just seen how the radius would of course change... Now I think I am more confused
 
Can you find a relationship between what the radius and the height is going to be when you're at a certain height up the cone? (hint: think similar triangles)
 
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