Solve Integral with Fourier Transform - Get Help Now!

doublemint
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Hello!
Can someone help me with this.
Evaluate:
the integral from zero to infinite of ((xcos(x)-sin(x))/x^3)cos(x/2)dx

I think it has to do with Fouriers Transform but I am just stuck.
Any help would be appreciated!
Thank You
 
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Thanks for the response fzero. There is one problem I have, my class has not covered the Dirichlet Integrals..Is there another method of solving this integral?
 
doublemint said:
Thanks for the response fzero. There is one problem I have, my class has not covered the Dirichlet Integrals..Is there another method of solving this integral?

It doesn't matter whether you covered them or not. I linked you to that page because it shows you how to evaluate them. Adapt the techniques to the integrals you have to do or find another way to do them.
 
doublemint said:
Thanks for the response fzero. There is one problem I have, my class has not covered the Dirichlet Integrals..Is there another method of solving this integral?
You could formally take the Fourier Transform. Let:

\mathcal{F}\left\{f(x)\right\}=\frac{1}{\sqrt{2 \pi }}\int _{-\infty }^{\infty }f(t)e^{i\omega t}dtand suppose that we are given:

<br /> \mathcal{F}\left\{\frac{x\cos(x)-\sin(x)}{x^3}\right\}=\frac{1}{4} \sqrt{\frac{\pi }{2}} \left(-1+w^2\right) (\text{Sign}[1-w]+\text{Sign}[1+w])

Where Sign(x) is either -1,0 or 1 depending on x being negative, zero, or positive. Can you now solve your integral?
 
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Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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