What Is the Gravitational Potential Energy of a Car on a 10-Degree Hill?

AI Thread Summary
The discussion focuses on calculating the gravitational potential energy of a 1000 kg car at the top of a 10-degree hill. The height of the hill is determined to be approximately 8.816 meters using the formula Height = 50 * Tan 10. The potential energy is then calculated using the formula PE = Mgh, resulting in approximately 86,484.96 joules. The calculations are confirmed as correct by another participant. The thread emphasizes the importance of accurate height and mass in potential energy calculations.
tica86
Messages
79
Reaction score
0
Car has a mass of 1000 kg its at a the top of a 10 degree hill. so if you were to draw a triangle the the base of the triangle would be 50 M in length as well.

a)what is it gravitational potential energy relative to the bottom of the hill?

Height = 50 * Tan 10
= 8.816

Potential energy =Mgh=1000 x 9.81 x 8.816 m=86484.96 J is this right?
 
Physics news on Phys.org
hi tica86! :wink:
tica86 said:
Car has a mass of 1000 kg its at a the top of a 10 degree hill. so if you were to draw a triangle the the base of the triangle would be 50 M in length as well.

a)what is it gravitational potential energy relative to the bottom of the hill?

Height = 50 * Tan 10
= 8.816

Potential energy =Mgh=1000 x 9.81 x 8.816 m=86484.96 J is this right?

looks ok! :smile:

(is something worrying you about it?)
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top