Solving Complex Fourier Series Problem - Help Needed!

AI Thread Summary
The discussion centers on a complex Fourier series problem involving the addition and subtraction of exponential terms. A user identifies an error in a textbook related to the expression involving exponentials, specifically pointing out a typo where π should be π/2. Another participant confirms this error and clarifies that for integer n, the terms simplify to eliminate the erroneous part. The conversation also touches on the correct trigonometric identities, emphasizing the distinction between cosine and sine representations. Overall, the thread provides a collaborative effort to resolve confusion around the Fourier series calculations.
Jag1972
Messages
40
Reaction score
0
Hello Folks,
I have a problem understanding a step of the complex Fourier series; it’s a step which involves simple addition and subtraction of exponentials (regrettably not simple for me).
I have attached a picture of the step I am having a problem with would really appreciate if someone could point me in the right direction.
Jag.
 

Attachments

  • ourier.JPG
    ourier.JPG
    53.4 KB · Views: 457
Engineering news on Phys.org
Yes there is indeed an error in that text, and it's in the line immediately following the one you marked with an asterisk.

The line following the one you marked should read (for simplicity I'll just give the bracketed part of the expression) :

( \, \, 2\, \exp(j n \pi/2) - 2\, \exp(-j n \pi/2) - [ \exp(j n \pi) - \exp(-j n \pi) ] \, \, )

This is simply collecting like terms right. Note however that for integer "n" that exp(j n Pi) is equal to exp(-j n Pi) so the "[]" term on the end goes to zero leaving just :

(\, 2\,\exp(j n \pi/2) - 2\,\exp(-j n \pi/2) \, )

This is what should have been shown in the bracketed term of the line following the one you indicated. Note that the book has a typo where they used Pi instead of Pi/2, but the Pi/2 magically reappears correctly in the final answer that follows.

So essentially it's just a typo on the part of the book. Does that clear it up for you?
 
Last edited:
UART: Thank you very much I was pulling my hair out trying to work it out. I have attached my working out following your reply is this right (I have shown the trig identities). Thanks :)
 

Attachments

UART: I have attached it as a JPEG as I think you may have to save the PDF to open.
 

Attachments

  • Fourier.JPG
    Fourier.JPG
    16.8 KB · Views: 454
Almost right.

Where you wrote :

"where cos(q) = (exp(jq) + exp(-jq))/2"

it would have made a lot more sense if you had of written :

"where j sin(q) = (exp(jq) - exp(-jq))/2
 
UART: Thanks again I wrote the wrong identity down doh! Its got to be sin\theta

Thanks again UART :)
 
Hi all I have some confusion about piezoelectrical sensors combination. If i have three acoustic piezoelectrical sensors (with same receive sensitivity in dB ref V/1uPa) placed at specific distance, these sensors receive acoustic signal from a sound source placed at far field distance (Plane Wave) and from broadside. I receive output of these sensors through individual preamplifiers, add them through hardware like summer circuit adder or in software after digitization and in this way got an...
While I was rolling out a shielded cable, a though came to my mind - what happens to the current flow in the cable if there came a short between the wire and the shield in both ends of the cable? For simplicity, lets assume a 1-wire copper wire wrapped in an aluminum shield. The wire and the shield has the same cross section area. There are insulating material between them, and in both ends there is a short between them. My first thought, the total resistance of the cable would be reduced...
I am not an electrical engineering student, but a lowly apprentice electrician. I learn both on the job and also take classes for my apprenticeship. I recently wired my first transformer and I understand that the neutral and ground are bonded together in the transformer or in the service. What I don't understand is, if the neutral is a current carrying conductor, which is then bonded to the ground conductor, why does current only flow back to its source and not on the ground path...

Similar threads

Back
Top