Electric Field over an infinite sheet

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SUMMARY

The discussion centers on calculating the electric field over an infinite sheet and a charged disk using the equations E = σ/2ε0 for the infinite sheet and E = σ/2ε0(1 - z/(z^2 + R^2)^1/2) for the charged disk. The method proposed involves subtracting the electric fields from both sources at a point P, confirming the correctness of the approach. The participants agree that the expression derived is valid for determining the resultant electric field.

PREREQUISITES
  • Understanding of electric fields and Gauss's Law
  • Familiarity with the concepts of charge density (σ) and permittivity (ε0)
  • Knowledge of vector subtraction in the context of electric fields
  • Basic calculus for handling the equations involving z and R
NEXT STEPS
  • Study the derivation of electric fields from charged surfaces using Gauss's Law
  • Explore the implications of charge density variations on electric field calculations
  • Learn about the superposition principle in electrostatics
  • Investigate the effects of boundary conditions on electric fields in different geometries
USEFUL FOR

Students in physics, electrical engineering majors, and anyone studying electrostatics who seeks to understand electric field calculations involving infinite sheets and charged disks.

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Homework Statement



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Homework Equations



E = σ/2ε0 (infinite sheet)
E = σ/2ε0(1 - z/(z^2 + R^2)^1/2) (charged disk)

The Attempt at a Solution



Is this the correct method below?

E = σ/2ε0 (infinite sheet) - [σ/2ε0(1 - z/(z^2 + R^2)^1/2)]
 
Last edited:
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yes...just subtract the independent fields due to infinite plane and the disc at point P. your expression is alright.
 

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