How to calculate heat flux in a hot water tank

AI Thread Summary
To calculate the heat flux on the bottom plate of an insulated hot water tank, the formula q = U A (T-water - T-outside) is recommended, where q is heat loss, U is the heat transfer coefficient, A is the surface area, T-water is the water temperature, and T-outside is the outside air temperature. The heat transfer coefficient U can be determined using the formula U = 1 / [ 1/hi + twall/kwall + tins/kins + 1/ho ], which incorporates factors like convection coefficients and material properties. The discussion emphasizes the importance of knowing the tank's insulation and positioning, as these affect heat transfer calculations. For those seeking software solutions, there are freeware options available for computing heat flux. Accurate calculations require specific values for the coefficients and temperatures involved.
chetanladha
Messages
59
Reaction score
0
Hi.
I wish to calculate the heat flux on a bottom plate of a hot water tank. Would simply (m*c*t)/area give me the correct results.
Please help?
 
Physics news on Phys.org
Is the bottom plate sitting on the ground or elevated? Is the tank insulated?
 
Thank you for your response.
Yes the tank is insulated,and sitting on ground.

Now the upper surface of plate is in contact with the fluid (hot water). How can i find the heat flux?
 
chetanladha said:
Thank you for your response.
Yes the tank is insulated,and sitting on ground.

Now the upper surface of plate is in contact with the fluid (hot water). How can i find the heat flux?
There are some nice "freeware" packages that will compute this. PM me if you are interested.

If you want to calculate it yourself, do this:

q = U A (T-water - T-outisde)

where,

q = heat loss
U = heat transfer coefficient
A = surface area
T-water = water temperature inside tank
T-outside = outside air temperature.

The heat transfer coefficient is given by:

U = 1 / [ 1/hi + twall/kwall + tins/kins + 1/ho ]

where,

hi = natural convection heat transfer coefficient on inside of tank
twall = tank wall thickness
kwall = tank thermal conductivity
tins = insultation thickness
kins = insulation thermal conductivity
ho = natural convection heat transfer coefficient on outside of tank

Let me know if you need any help figure these values out.
 
This is from Griffiths' Electrodynamics, 3rd edition, page 352. I am trying to calculate the divergence of the Maxwell stress tensor. The tensor is given as ##T_{ij} =\epsilon_0 (E_iE_j-\frac 1 2 \delta_{ij} E^2)+\frac 1 {\mu_0}(B_iB_j-\frac 1 2 \delta_{ij} B^2)##. To make things easier, I just want to focus on the part with the electrical field, i.e. I want to find the divergence of ##E_{ij}=E_iE_j-\frac 1 2 \delta_{ij}E^2##. In matrix form, this tensor should look like this...
Thread 'Applying the Gauss (1835) formula for force between 2 parallel DC currents'
Please can anyone either:- (1) point me to a derivation of the perpendicular force (Fy) between two very long parallel wires carrying steady currents utilising the formula of Gauss for the force F along the line r between 2 charges? Or alternatively (2) point out where I have gone wrong in my method? I am having problems with calculating the direction and magnitude of the force as expected from modern (Biot-Savart-Maxwell-Lorentz) formula. Here is my method and results so far:- This...
Back
Top