Two coplanar lines and finding the equation

  • Thread starter Thread starter gundamshadow
  • Start date Start date
  • Tags Tags
    Lines
AI Thread Summary
Two coplanar lines, a and b, are perpendicular, with line a defined by points (3,2,3) and (8,10,6). The equation for line b needs to be determined, passing through the point (7,49,25). The initial approach involved using the cross product to find a direction vector for line a. To find the equation for line b, it is suggested to identify vectors in the plane and utilize properties of the normal vector. Further exploration of vector relationships and the plane's normal is recommended for solving the problem.
gundamshadow
Messages
7
Reaction score
0

Homework Statement


Two coplanar lines, a and b are perpendicular to each other. a passes through the points (3,2,3) and (8,10,6). Find the equation for b if it passes through the point (7,49,25).


Homework Equations


The equation were trying to find is r = [x,y,z] + s [x1,y1,z1] + t [x2,y2,z2]



The Attempt at a Solution


Basically since the coordinates are perpendicular I used the cross product to find one direction vector. For my position vector I used (3,2,3). Now I'm not sure what to do with the last point (7,49,25) or what to do to find my second direction vector. I'm not even sure if I did the first part right. Help would be appreciated thanks!
 
Physics news on Phys.org
gundamshadow said:

Homework Statement


Two coplanar lines, a and b are perpendicular to each other. a passes through the points (3,2,3) and (8,10,6). Find the equation for b if it passes through the point (7,49,25).


Homework Equations


The equation were trying to find is r = [x,y,z] + s [x1,y1,z1] + t [x2,y2,z2]



The Attempt at a Solution


Basically since the coordinates are perpendicular I used the cross product to find one direction vector. For my position vector I used (3,2,3). Now I'm not sure what to do with the last point (7,49,25) or what to do to find my second direction vector. I'm not even sure if I did the first part right. Help would be appreciated thanks!

Hi gundamshadow, Welcome to PF.

Your question, being mathematical in nature, would probably fair better in the Precalculus forum. But I can give you a hint or two here :smile:

The lines involved are said to be coplanar, and that plane must have a normal. A plane's normal has some nice properties involving vectors in the plane and cross and dot products. You might want to look into that :wink:

You might start by finding any two vectors in the plane from the given points...
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
Back
Top